Physics: Post your doubts here!

[Hadi Murtaza]

So, lemme explain you...
R = V / I yes ?
It means R is in the ratio of V : I yes ?
And we are given I - V graph yes ?
So we can draw a line of best fit, that is from origin, and the line of best fit here is resistance.
And we are asked to find the least resistance in the whole graph..
We are given points A,B,C,D..
Now you attach all point from origin to A,B,C,D
you'll see The steepest line at C point... (Steepest the gradient lower will be the Resistance, hope you got the answer, if no lemme elaborate)
And as you know, R = 1/m yes ? ; so, High the m, less is the R : Here we have the steepest line at C then answer is C
Well, if we were asked for the highest resistance, answer would be D, as it has the lowest steepness from other three.
Hope you got it

U dont calculate gradient by joing a point wid origin -_-

 

[Thought blocker]

U dont calculate gradient by joing a point wid origin -_-

arey bhai... dekho...
Steepest line means it has highest gradient, which is when you join it to C point dear...
suno... maine yeh kaha hain.. ki high the m less is R, so high the steepness, less is R..
Hope now you get me
if not don't hesitate to ask

 

[Thought blocker]

U dont calculate gradient by joing a point wid origin -_-

Hadi, agar abhi bhi shamajh na aya ho na... meko inbox kardo kya shamajh nahi aya I'll explain there, yaha pe sab ko alerts mil rahi hogi . _ .

 

[Hadi Murtaza]

http://www.wolframalpha.com/input/?i=y+=+-(x-4)²+++10

arey bhai... dekho...
Steepest line means it has highest gradient, which is when you join it to C point dear...
suno... maine yeh kaha hain.. ki high the m less is R, so high the steepness, less is R..
Hope now you get me
if not don't hesitate to ask

Look at dis curve

 

[Hadi Murtaza]

http://www.wolframalpha.com/input/?i=y = -(x-4)² + 10

Look at dis curve

Wat is da gradient at da maximum point ?

 

[Thought blocker]

http://www.wolframalpha.com/input/?i=y = -(x-4)² + 10

Look at dis curve

Then ?

 

[Thought blocker]

Wat is da gradient at da maximum point ?

from zero to 8 or -40 to 40 ?

 

[Hadi Murtaza]

from zero to 8 or -40 to 40 ?

both r da same graphs

 

[Hadi Murtaza]

both r da same graphs

look at 0 to 8

 

[Thought blocker]

look at 0 to 8

Differentiation karkey nikal lo ._. LOL

 

[Thought blocker]

both r da same graphs

Oh, poor me ._.

 

[Hadi Murtaza]

Differentiation karkey nikal lo ._. LOL

yup nikalo, waise at maximum or minimum oint gradient is always 0

 

[Thought blocker]

yup nikalo, waise at maximum or minimum oint gradient is always 0

Nikal ke kiya karna hain ?
wo batado ._.
meko ye nai ata diff wala ._.
tum sikado . _ .

 

[Hadi Murtaza]

Nikal ke kiya karna hain ?
wo batado ._.
meko ye nai ata diff wala ._.
tum sikado . _ .

Wat im saying is dat, da method u did on dat physics question will b wrong here

 

[Hadi Murtaza]

Nikal ke kiya karna hain ?
wo batado ._.
meko ye nai ata diff wala ._.
tum sikado . _ .

Differentiation nhi aati ?

 

[Thought blocker]

Wat im saying is dat, da method u did on dat physics question will b wrong here

Are bhai............................ WO I-V GRAPH THA AND R WAS LINE OF BEST FIT AND THE STEEPEST CURE MEANS LOW RESISTANCE HENCE ANSWER WAS C :/

Differentiation nhi aati ?

-2(x-4) ata hain na ?

 

[Hadi Murtaza]

Are bhai............................ WO I-V GRAPH THA AND R WAS LINE OF BEST FIT AND THE STEEPEST CURE MEANS LOW RESISTANCE HENCE ANSWER WAS C :/

-2(x-4) ata hain na ?

Are bhai............................ WO I-V GRAPH THA AND R WAS LINE OF BEST FIT AND THE STEEPEST CURE MEANS LOW RESISTANCE HENCE ANSWER WAS C :/

-2(x-4) ata hain na ?

yups

 

[Thought blocker]

yups

Bas to wo method se agar tum ko karna ho... Gimme points like we had on phy quest... ABCD me tum ko bata dunga at which point it is highest....

Bas meko ati to hain, but what should we take X as ? :/

 

[Hadi Murtaza]

Are bhai............................ WO I-V GRAPH THA AND R WAS LINE OF BEST FIT AND THE STEEPEST CURE MEANS LOW RESISTANCE HENCE ANSWER WAS C :/

-2(x-4) ata hain na ?

2 find coordinates of a stationary point, u put dy/dx = 0 , n solve for x

 

[Thought blocker]

2 find coordinates of a stationary point, u put dy/dx = 0 , n solve for x

Orey han, bhul gaya tha..