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CB also has resistance. So there is some voltage across it too. The rest of the voltage is then equally dissipated across the two parallel wires
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CB also has resistance. So there is some voltage across it too. The rest of the voltage is then equally dissipated across the two parallel wires
okay so it is very simple:
difference in pressure = rho g (difference on height)
difference in height= 6
only D and C had difference of 6
the height of column attached to high pressure will have smaller height.
so D is answer.
thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
thanks in advance. Suchal Riaz
Sure :
5a)
its easier if u convert the angle in radian ie multiply by (π/180°) ----> 60° = π/3 rads.
n c this --->
thts whr the new wave will start!
So it would look like :
Correct me if it is wrong. ZaqZainab Suchal Riaz
thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
bi)thank u very much but i dont think i asked abt the current question. the actual question is question 6b) from :
papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
thanks in advance. Suchal Riaz
Not sure. Suchal Riaz ZaqZainab usama321http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_21.pdf
"Q6(ii) " sketch would be appreciated
Straight line at start, and then curves downwards... but NEVER horizontalNot sure. Suchal Riaz ZaqZainab usama321
Well is a st line till 3A and 12 V and then curve.View attachment 39465
Not sure. Suchal Riaz ZaqZainab usama321
Well is a st line till 3A and 12 V and then curve.View attachment 39465
Suchal Riaz is this correct ?Sure :
5a)
its easier if u convert the angle in radian ie multiply by (π/180°) ----> 60° = π/3 rads.
n c this --->
thts whr the new wave will start!
So it would look like :
Correct me if it is wrong. ZaqZainab Suchal Riaz
Hey can you please explain Q6(c) alsoStraight line at start, and then curves downwards... but NEVER horizontal
Still in As, maybe next yearhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf @ ninjaln Pyjamas,usama321,biscuitbiscuit,Mohammmed salik
please explain Q10 c 2
and Q9 b2
16:
B is incorrect because the velocity does not decrease uniformly (it's roughly parabolic), which means height of the ball does not increase uniformly, which means the potential energy of the ball does not increase uniformly (since Ep = mgh and rate of h is not constant).
26:
HOPE IT HELPS
-->Intensity is directly propotional to square of aEmm i dont find any explanation for 26 but thanks for helping with 16
change in U = Work done against weightView attachment 39472
MS :
force on mass = mg (where g is the acceleration of free fall
/gravitational field strength)
g = GM/r^2
if r @ h, g is constant
ΔEP = force × distance moved
= mgh
okay so the range is from 1.5 to 3.5 V for 0-25 CHey can you please explain Q6(c) also
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w10_qp_22.pdf
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