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You deserved so.I feel honored
NOis Thermal Physics included in As level ??
Anytimecool!! then too light syllabus it is .. The thing is k I forgot all and messed up. with what is in A level and As level. Thank u for the assistance
stress = force / areaCan someone please help me with q4 part c. Thanks
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
Is that the minimum area of the wire?stress = force / area
For max area, we need to know min area so,
Force= 1.9*10^3 , Stress= 9.5*10^8 We got stress from b part
so min area= F/S
=(1.9*10^8)/(9.5*10^8)
=2*10^-6
So for max area= Cross-sectional area-min area
=(3.2*10^-6)-(2*10^-6)
=1.2*10^-6 (FINAL ANSWER)
Minimum area is 2*10^-6Is that the minimum area of the wire?
IT WAS BRITTLE SO, ITS RELATED TO THAT ( I AM NOT SURE ABOUT THIS )Btw, i still don't understand the concept behind it. How does the sphere contribute to making the wire unbreakable
Thank you so much!
Very simple.Suchal Riaz
Can you please help me with this question
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w07_qp_2.pdf
4c. I can't understand the concept behind it.
This was what I said, usama321 or I was wrong ??? Suchal Riaz ??? I am not getting, I told was same only, wasn't it ?Very simple.
Find the minimum area for which the rod doesn't break then subtract that from the total area of wire to find the maximum area of bubble.
This might help you: View attachment 38254
Ohk, thanks For the bubble to have the maximum area, the wire needs to have the minimum area, and the rest is occupied by the bubble. ThanksVery simple.
Find the minimum area for which the rod doesn't break then subtract that from the total area of wire to find the maximum area of bubble.
This might help you: View attachment 38254
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