• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Physics: Post your doubts here!

Messages
960
Reaction score
3,500
Points
253
A loudspeaker incident and the sound received by a microphone or source detector. We put the detector as close to the glass to avoid reflection of sound and the detector behaves in such a way we want to know the details about the sound wave at the glass window, my thought though, I am doing it right now btw, what about the second question where they ask to draw best and worst fit line I don't get it

yeah i don't get the way we have to insert the vacuum pump and the strain gauge :/
best fit line is the one that passes through all the plotted points except the anomalies
worst acceptable line is the one that passes through all the error bars (from the top of the first error bar to the bottom of the last error bar, or vice versa )
 
Messages
4
Reaction score
3
Points
11
Re: Physics Help here! Stuck somewhere?? Ask here! :)
please can anyone post any solved paper5, q2 here ...i have problem with plotting the error bars. plzzzz help anyone :(
my prayers will always be for u....ia
 
Messages
168
Reaction score
50
Points
38
yeah i don't get the way we have to insert the vacuum pump and the strain gauge :/
best fit line is the one that passes through all the plotted points except the anomalies
worst acceptable line is the one that passes through all the error bars (from the top of the first error bar to the bottom of the last error bar, or vice versa )


I don't think that is anything necessary to write because data collection is 5 marks, 1 for drawing, 1 for how to measure the value of the independent variable, 1 for dependent variable, and 2 marks to measure the other controlled variables. There is a vacuum pump somehow but I don't know how it works but it's enough to say you need the vacuum pump since all are one mark each. Simply mention it in bullet points as my revision guide suggested rather than how you actually do it by hand just say the apparatus for whichever it is.
 
Messages
960
Reaction score
3,500
Points
253
I don't think that is anything necessary to write because data collection is 5 marks, 1 for drawing, 1 for how to measure the value of the independent variable, 1 for dependent variable, and 2 marks to measure the other controlled variables. There is a vacuum pump somehow but I don't know how it works but it's enough to say you need the vacuum pump since all are one mark each. Simply mention it in bullet points as my revision guide suggested rather than how you actually do it by hand just say the apparatus for whichever it is.



but i think it is necessary to include it in the diagram as far as i know :/
Thanx though!
 
Messages
218
Reaction score
22
Points
28
Guys my grade components in AS are AAC. Im hoping to get AA in A2 so can I get an A* with all As and a C in Paper 3?
 
Messages
168
Reaction score
50
Points
38
but i think it is necessary to include it in the diagram as far as i know :/
Thanx though!


Nope, "arrangement of apparatus and procedures to be followed" procedures can be described just by the apparatus for which quantity
 

Attachments

  • IMG-20130529-00082.jpg
    1 MB · Views: 15
  • IMG-20130529-00084.jpg
    938.9 KB · Views: 14
Messages
1,394
Reaction score
1,377
Points
173
in that 31 questions
Q25) Drawing the waveforms, l=1/4wavelength in X and l=1/2 wavelength in Y. As the speed of sound is constant, the ratios of the frequencies should be reciprocal to the ratio of wavelengths, that would be frequency of X:Y = 1:2. So frequency of Y is double of the frequency of X.
Q31) Conduction wires conduct due to mobile electrons, so C and D are incorrect. The movement of electrons random, so B is eliminated. A is correct.

3. Q23) I'm not entirely sure of this but the extension is denoted by W/k. Now P and Q have identical spring constants so total extenion = 2. Now PQ and R are taken in series so product over sum gives us the answer.

4. Q12) SOMEONE PLEASE SOLVE THIS FOR ME TOO.

5. Q12) R1 and R2 both act against the weight of the frame so their magnitude would be equal. T1 has a greater horizontal component than T2, the vertical one is in the same line of force as the weight and R for both and is not considered, so wire T1 is more tensed upp. More like how picture frames fall when you suspend them with too short a wire and they snap. Real life scenarios. ;)

And I had a powercut scheduled in the middle so the 3 seperate posts. Sorry. :p
there is no current in the wire so what were you saying about the C and D being incorrect because curent only passes with mobile electrns?
 
Messages
15
Reaction score
6
Points
3
in that 31 questions
there is no current in the wire so what were you saying about the C and D being incorrect because curent only passes with mobile electrns?

Delocalised or 'mobile' electrons are called so because they are never stable or in a fixed place. They move about. That being my point here on eliminating the two options, Miss T. :p
 
Messages
960
Reaction score
3,500
Points
253
Nope, "arrangement of apparatus and procedures to be followed" procedures can be described just by the apparatus for which quantity

Owhhh okay....hmmm.... although our teacher told us that it is necessary to include all the apparatus in the diagram!
Thanx a lot for clarifying that....
 
Messages
1,394
Reaction score
1,377
Points
173
Delocalised or 'mobile' electrons are called so because they are never stable or in a fixed place. They move about. That being my point here on eliminating the two options, Miss T. :p
hahahaha.... Meeeesshhaa! :p thanksuu xD
 
Messages
1,394
Reaction score
1,377
Points
173
i got help from a friend on that one...
its 120a = 120g - T (its F=ma for LHS and T is tension) --> for the barrel

80a = T - 80g ---> for the man

adding the 2 equaitons u get
200a = 40g
a = 1.962 [whn u take g=10ms^-2]

man is level with the barrel when both have covered the same distance:
18/2 = 9m [acceleration is same for both so both have travelled same distance]

2as = v2 - u2
2(1.962)(9) = v^2
v = 5.94 = 6 [approx.]
 
Messages
189
Reaction score
118
Points
28
in paper 5 graph question .. do we hav 2 extrapolate the graph till origin or just til the points? i have no teacher so i need help !! :rolleyes: and how many significant figures for all answers?
 
Messages
355
Reaction score
95
Points
38
Q25) Drawing the waveforms, l=1/4wavelength in X and l=1/2 wavelength in Y. As the speed of sound is constant, the ratios of the frequencies should be reciprocal to the ratio of wavelengths, that would be frequency of X:Y = 1:2. So frequency of Y is double of the frequency of X.
Q31) Conduction wires conduct due to mobile electrons, so C and D are incorrect. The movement of electrons random, so B is eliminated. A is correct.

3. Q23) I'm not entirely sure of this but the extension is denoted by W/k. Now P and Q have identical spring constants so total extenion = 2. Now PQ and R are taken in series so product over sum gives us the answer.

4. Q12) SOMEONE PLEASE SOLVE THIS FOR ME TOO.

5. Q12) R1 and R2 both act against the weight of the frame so their magnitude would be equal. T1 has a greater horizontal component than T2, the vertical one is in the same line of force as the weight and R for both and is not considered, so wire T1 is more tensed upp. More like how picture frames fall when you suspend them with too short a wire and they snap. Real life scenarios. ;)

And I had a powercut scheduled in the middle so the 3 seperate posts. Sorry. :p

very very helpful thanks
 
Top