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Physics, Chemistry and Biology: Post your doubts here!

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Can anyone describe an experiment to find the Specific latent heat of steam please?
 
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Can anyone describe an experiment to find the Specific latent heat of steam please?
you bring these equipment :
electric heater
beaker
water
stopwatch
mass balance
1) when the water in the beaker is boiling the mass reading on the balance is noted and a stopwatch is started. A few minutes later the stopwatch is stopped and the mass reading is taken again
2) the difference in the mass reading gives the madd of water which has been changed into steam during the time measured
therefore you can claculate the specific latent heat of steam by the equation :
Lv = Pt /m
 
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Can anyone describe an experiment to find the Specific latent heat of steam please?
latent heat of steam, or more commonly called the heat of vaporization of water, is the amount of heat (energy) required to boil a kg of water at 100C, converting it to steam at 100C, or conversely, the amount of heat (energy) 1 kg of steam at 100C gives off as it condenses back to water at 100C. The two numbers are the same.

the apparatus u'll need is a thermometer to find initial n final temp. wid water in a beaker wid its known mass n use d formula 2 calculate it:Q=m x c x temperature diff.__________hope it helped!
 
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can anyone explain barometer and manometer please?? i dont get them :(
Barometer is used to measure atmospheric pressure the liquid in it is usually mercury and it is usually 76 cm at sea level
Manometer measures pressure of a gas in a closed container it is usually in a U-shape, the liquid is mercury because of its high density.
 
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I'm sorry...what's your question? Coz it's kinda hard to make out.
How about posting the paper link instead? :p
No, no. Apparently the papers have been leaked or sth in Kuwait, and there's this guy from there who's posted an image of tomorrow's paper. (Check out the date on the paper. And it doesn't seem photoshopped.) Probably a spoof, but still.
 
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Hard worker, eh?
... One sec, how CAN they LEAK the paper? It'll be of another variant, if so. And what in the WIDE cosmos is wrong in seeing another variants' papers?
They repeat quite a few questions. Don't see that stupid image, for the love of God. I mean, quite literally.
 
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View attachment 43017
eureka! now see- Voltage is same in lamps X and Y, right? So when Y is removed, why is it making Z dimmer?
See, resistance ka formula in parallel is (R1xR2)/(R1+R2). So total resistance is always lesser than resistance of any of the lamps. When Y is removed, resistance across X will increase, so p.d. across it will also increase., reducing p.d. across Z. Hope it helps!
 
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