Paper 1 Chemistry Tomorrow D:

[LeenBuscus]

Haaaii everyone c:
Are you ready for tomorrow's paper?
And what last minute preparations are you doing?
According to the level of difficulty you faced in the previous chem papers what are your expectations for tomorrow and do you think it will be tricky?
Oh and good luck to everyone

 

[kitkat <3 :P]

papers papers and papers ._.

 

[omaaaar]

Had 14 days to prepare for the paper wasted almost all the time now I am regretting but don't know what to do now hope paper comes easy tomorrow

 

[LeenBuscus]

Had 14 days to prepare for the paper wasted almost all the time now I am regretting but don't know what to do now hope paper comes easy tomorrow

You just summarized my whole year in one sentence xD

 

[omaaaar]

You just summarized my whole year in one sentence xD

So can u tell me wat you are doing at the moment for the preparation

 

[LeenBuscus]

So can u tell me wat you are doing at the moment for the preparation

Solving pastpapers and going through the syllabus points that I have a problem in... and reading solved papers to know the answers and understand them c: what about you?

 

[oahmed64]

can anyone solve n13 p13 q32 please ?

 

[omaaaar]

Solving pastpapers and going through the syllabus points that I have a problem in... and reading solved papers to know the answers and understand them c: what about you?

Reading some parts from the books which I don't remember and doing random questions from past papers
Gud luck to u for tomorrow's paper

 

[LeenBuscus]

can anyone solve n13 p13 q32 please ?

m/j or o/n?

 

[oahmed64]

m/j or o/n?

november

 

[LeenBuscus]

november

it is C because the graph has nothing to do with 1 concentration it is talking about number of molecules...
2 is right because increasing temp increasing energy so can be represented on graph
3 is right becaue adding catalyst decreasing Activation energy so can be represented on graph c:

 

[..sacrifice4Revenge..]

anyone having any queries, post in this thread..
https://www.xtremepapers.com/commun...st-your-doubts-here.9859/page-540#post-827557

 

[Princess1997]

does anybody have summer and winter question paper 2001
i REALLY NEED THEM

 

[omaaaar]

does anybody have summer and winter question paper 2001
i REALLY NEED THEM

Oct nov 2001 is on free exam papers.com

 

[oahmed64]

thanks and please also june2013 p11 q11

 

[Al-Anoud]

 

[LeenBuscus]

thanks and please also june2013 p11 q11

get the n for SnCl2... (9.5/190) = 0.05
get oxidation state of Mn in MnO4^- (-1=x-8) = 7
so Mn +7 changes to Mn +2 therefore reduced by 5
and Sn +2 changes to Sn +4 so oxidised by two
in redox oxidised must equal reduced so multiply both equations one by 2 and the other by 5 to get
5Sn^+2 -> 2Mn^+5 ... and then cross multiply with the SnCl2 n
0.05 .......... x
so 2(0.05) divided by 5
and the answer is B... 0.02

 

[dumb human]

it is C because the graph has nothing to do with 1 concentration it is talking about number of olecules...
2 is right because increasing temp increasing energy so can be represented on graph
3 is right becaue adding catalyst decreasing Activation energy so can be represented on graph c:

Chemistry June 2013, Paper 1_2 Question 31?? y A?

 

[LeenBuscus]

Chemistry June 2013, Paper 1_2 Question 31?? y A?

~~~Al has 13 e and as a -2 ion it has 15 e
and O has 16 and as a + ion it has 15 e
so they're both on same p orbital in electronic configuration... so 1 is right
~~~N has 7 e and the +2 ion of Cl has 15 e
the electric config of N is 1S2,2S2,2P3
the electc config of Cl +2 is 1S2,2S2,2P6,3S2,3P3
so both have 3 e in P shell so 2 is right
~~~C has 6 e and Cl+ has 16 e
the electric config of C is 1S2,2S2,2P2
the electric config if Cl+ is 1S2,2S2,2P6,3S2,3P4
but because electrons occupy all empty orbitals before pairing up... it will look like |^v|^|^| in the box and arrow notation so two unpaired just like in C so 3 is right

 

[dumb human]

~~~Al has 13 e and as a -2 ion it has 15 e
and O has 16 and as a + ion it has 15 e
so they're both on same p orbital in electronic configuration... so 1 is right
~~~N has 7 e and the +2 ion of Cl has 15 e
the electric config of N is 1S2,2S2,2P3
the electc config of Cl +2 is 1S2,2S2,2P6,3S2,3P3
so both have 3 e in P shell so 2 is right
~~~C has 6 e and Cl+ has 16 e
the electric config of C is 1S2,2S2,2P2
the electric config if Cl+ is 1S2,2S2,2P6,3S2,3P4
but because electrons occupy all empty orbitals before pairing up... it will look like |^v|^|^| in the box and arrow notation so two unpaired just like in C so 3 is right

oooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh finnalieeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee iiiiiiiiiiiiiiiiiii gooooooooooooooooooooooooooooot iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiit =D thaaaaaaaaaaaaaaaaaaaaank yooooooooooooooooooou =P