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Maths (Paper 3)
- Thread starter diwash
- Start date
well madiha
if u square both sides u will get an anser of
-0.5<x<1.25
now chek if ur anser is correct
take for the range below -0.5 it will be incorrect
now take an x value of btween -0.5 and 1.25 it will be CORRECT
now take a value more than 1.25 it will also Be CORRECT
so we come to a conclusion that x can be greater than 1.25 so we eliminate that choice so all we get is
-0.5<x
if u square both sides u will get an anser of
-0.5<x<1.25
now chek if ur anser is correct
take for the range below -0.5 it will be incorrect
now take an x value of btween -0.5 and 1.25 it will be CORRECT
now take a value more than 1.25 it will also Be CORRECT
so we come to a conclusion that x can be greater than 1.25 so we eliminate that choice so all we get is
-0.5<x
For solving modular equations:
1.
Check that you have the right number of solutions Be careful when solving equations involving a modulus function that you have the correct number of solutions. Sketching a graph is helpful, and you should also check your solution(s) by substituting back into the original equation.
2.
Take care with inequality signs, especially when they involve negative numbers When solving inequalities involving a modulus sign, be very careful with the inequality symbol. Remember that you need to reverse it if you are multiplying or dividing through by a negative number. Check your answer by substituting a number from within the solution set into the original inequality.
1.
Check that you have the right number of solutions Be careful when solving equations involving a modulus function that you have the correct number of solutions. Sketching a graph is helpful, and you should also check your solution(s) by substituting back into the original equation.
2.
Take care with inequality signs, especially when they involve negative numbers When solving inequalities involving a modulus sign, be very careful with the inequality symbol. Remember that you need to reverse it if you are multiplying or dividing through by a negative number. Check your answer by substituting a number from within the solution set into the original inequality.
zeebujha said:
No, there is a numerical method. All you have to do is solve for the two answers and check the solution for both of them. One will not fit because the modulus will cancel the negative of one side and so only one solution can be taken.
Reference: J2006 q2
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mukesh can u plz solve q-7 of oct nov 2010 variant 31,step wise plz.its the same perpendicular question as u stated above,but those alphabets are confusing me ,can u help me as Asap,or anyone of u can help plz>>>>>
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ParanoidAleveler said: