• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Maths Paper 3 doubt

Messages
204
Reaction score
81
Points
38
Can someone out there please help me with the inequality  l x − 2 l < 3 − 2x. I used to solve these kinda problems with the general method of squaring on both side but the answer to this question does not matches to that of the marking scheme. The ms suggests the answer to be just x < 1 but I got x < 1 and x > 5/3 , now how am I supposed to eliminate the 5/3 part o_O ? Please help asap. Thanks in advance (y) .
 
Messages
83
Reaction score
47
Points
28
l x − 2 l < 3 − 2x
x-2<3-2x or -(x-2)<3-2x
-5<-3x or -x+2<3-2x
5/3>x or -1<-x ==> x<1 & x<1.67 (5/3=1.67)

Hence we can simply say x<1 ; no need to write x<1.67.
 
Messages
42
Reaction score
11
Points
8
l x − 2 l < 3 − 2x
x-2<3-2x or -(x-2)<3-2x
-5<-3x or -x+2<3-2x
5/3>x or -1<-x ==> x<1 & x<1.67 (5/3=1.67)

Hence we can simply say x<1 ; no need to write x<1.67.

Should not it be X<1.67 ? Because for x<1 & x<1.67,if we write x<1 then are not we omitting the values bigger than 1 and smaler than 1.67?
 
Top