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LHSView attachment 60864
in (i), I take the left-hand side and apply double-angle identity for cos, but what follows?...confused
View attachment 60864
in (i), I take the left-hand side and apply double-angle identity for cos, but what follows?...confused
Hello im having difficulties in paper june 2013 paper 32 question 9
Im unable to shade the required region and find the greatest value of |z|.
Please help....
Thxx in advance
For access to detailed worked solutions for P1, P3, M1 and S1 from Year 2005 to Year 2015 at only 10 USD.View attachment 60868
CIE M/J 2014 V42 Q2
The time at which the two particles collide is T. So the distance covered by particle Q during this time, T can be calculated using:View attachment 60868
CIE M/J 2014 V42 Q2
you should know differentiation of tan x = sec^2x not integration. Integration of tan x = - ln |cosx|Hi....I need to integrate tan 2x.
I'm confused as why i need to convert it to sin 2x/cos 2x first.
Can't I just do: (sec^2 2x)/2 + c
(The answer is -0.5 ln cos 2x +c)
Help please?
Hi....I need to integrate tan 2x.
I'm confused as why i need to convert it to sin 2x/cos 2x first.
Can't I just do: (sec^2 2x)/2 + c
(The answer is -0.5 ln cos 2x +c)
Help please?
Yep that's an A for sureI am got 70% in As level (b) and now I am getting almost 60/75 in P3 and 40/50 in S2. Will I be able to get an A ?
Thanks.
Thank you!you should know differentiation of tan x = sec^2x not integration. Integration of tan x = - ln |cosx|
use reverse chain rule to get the integral of tanx
good luck
If I got 35 in stats than? xDYep that's an A for sure
WelcomeThank you!
For the one triangle BXC :guys i need help with question #9(b) on this paper...........
please help!!!!!!!!!!!!!!!!!!!!
Then B or also A BTW why ru giving againIf I got 35 in stats than? xD
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