Mathematics: Post your doubts here!

[Anum96]

View attachment 58034
last part

Did you try partial fractions?

 

[happyoner_5]

Mass = 1100
Fd = 1800
Fr = 700N
Distance = x
Speed = v
i) K.E = 1/2(1100)v^2 = 550v^2
P.E = (1100)(10)(160) = 1760000 Now we have to find it in terms of x which is distance. So it will become 1760000/1760 = 1000x

kv^2 = x
1800x = 700x+ 550v^2+ 1000x
^This is the WD equation. I just substituted everything in terms of x and v
Solve it further you will get
100x = 550v^2
x = 550/100v^2
x = 5.5v^2
Hence k = 5.5 Ans.

ii) 5.5v^2 = 1760
v^2 = 320

1800(x-1760) = 700(x-1760)+ 550(v^2-320) [we subtracted 320 because it was our initial velocity and so to find gain in K.E we already have v^2(initial velocity)
1800x-3168000 = 700x - 1232000+ 550v^2 - 176000
1800x-700-3168000 = -1408000+ 550v^2
1100x-3168000+ 1408000 = 550v^2
1100x+ 1760000 = 550v^2
(1100x+ 176000)/550 = v^2
v^2 = 2x - 3200 (shown)

thnx a lot : )

 

[Copy Cat]

take lcm
dh/dt = (100-h^2)/20h^2
(20h^2/(100-h^2)) dh = dt
Use result from part 2.
-20 + 2000/(10-h)(10+h) dh = dt
use partial fractions
-20 + 100/(10-h) + 100/(10+h) dh = dt
then integrate

Did you try partial fractions?

Thaks a lot
Yes i did but my C is zero just wanted to confirm because in ms there's no correct answer given.

Btw in 2 nd part can we just say assume h=1 anwers are 2/100 and 2/99 so since the answers are close enough hence we can say that they are eqivalent

 

[DaniyalK]

Thaks a lot
Yes i did but my C is zero just wanted to confirm because in ms there's no correct answer given.

Btw in 2 nd part can we just say assume h=1 anwers are 2/100 and 2/99 so since the answers are close enough hence we can say that they are eqivalent

Both of those things are in the examiner report.

 

[happyoner_5]

can u plz suggest a good book for further math

 

[DaniyalK]

can u plz suggest a good book for further math

Further Pure Mathematics by Brian and Mark Gaulter
A Concise Course in Advanced Level Statistics by Crawshaw and Chambers
Mechanics for A Level by Bostock and Chandler

They don't cover all the topics, but you can find the majority of them in these books.

 

[happyoner_5]

Further Pure Mathematics by Brian and Mark Gaulter
A Concise Course in Advanced Level Statistics by Crawshaw and Chambers
Mechanics for A Level by Bostock and Chandler

They don't cover all the topics, but you can find the majority of them in these books.

thnx

 

[Wâlèé Atèéq]

https://drive.google.com/file/d/0B6rlbmTCHUFZRm0tN2RkZEJVNW8/view?usp=sharing

Q8..! Mechanics..? need help..!

 

[***amd***]

https://drive.google.com/file/d/0B6rlbmTCHUFZRm0tN2RkZEJVNW8/view?usp=sharing

Q8..! Mechanics..? need help..!

consider points A and C, u have...
time = 6s
displacement = 60m
initial velocity = 4 m/s

use s = ut + 1/2 at^2, and u get a = 2 m/s^2

now that u have acceleration,
consider points A and B,
time = 3s
initial velocity = 4 m/s
acc = 2

use again s = ut + 1/2 at^2
s = 21 m

 

[Wâlèé Atèéq]

consider points A and C, u have...
time = 6s
displacement = 60m
initial velocity = 4 m/s

use s = ut + 1/2 at^2, and u get a = 2 m/s^2

now that u have acceleration,
consider points A and B,
time = 3s
initial velocity = 4 m/s
acc = 2

use again s = ut + 1/2 at^2
s = 21 m

Thanx bro..!

 

[extremesuser]

https://mathway.com/

 

[The Sarcastic Retard]

(iii)

 

[Anum96]

View attachment 58090
(iii)

http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-rcostheta-alpha-2009-1.pdf
Use these notes for these type of questions. You will find what u need in the last heading that's all about maximum and minimum values

 

[The Sarcastic Retard]

http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-rcostheta-alpha-2009-1.pdf
Use these notes for these type of questions. You will find what u need in the last heading that's all about maximum and minimum values

Thanks

 

[The Sarcastic Retard]

http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-rcostheta-alpha-2009-1.pdf
Use these notes for these type of questions. You will find what u need in the last heading that's all about maximum and minimum values

Can u please post the solution. I already refered to this site.. nahi aa raha meko

 

[Anum96]

Can u please post the solution. I already refered to this site.. nahi aa raha meko

Sure. Wait up
Whats the answer ? I'll post if I get it correct

 

[The Sarcastic Retard]

Sure. Wait up
Whats the answer ? I'll post if I get it correct

IDK no solution with me thats why m confused.
its a homework :3

 

[***amd***]

https://mathway.com/

F.Z.M. 7
"All" kinds of maths homework problems...

 

[Anum96]

IDK no solution with me thats why m confused.
its a homework :3

Well, I cant be 100 % sure here, but here's what I did.
Greatest value of cosine is 1. You will get that when 1/2(theta) is 360
greatest value of sin is also 1. You will get that when 1/2(theta) is 90
Therefore plugging in 1 will give you 7 plus 5 plus 12 which is 24
Now 24 is the greatest value that occurs. For the smallest 'positive' however, you need a positive sign will the largest number i.e. 12 and a negative sign with 5 to get the smallest value. Therefore 1-5 12 will give you 14.
For less working you can even use your answer to part i and then determine cos and sin values
I repeat I'm not sure if that's correct. That was my mental calculation

 

[The Sarcastic Retard]

Well, I cant be 100 % sure here, but here's what I did.
Greatest value of cosine is 1. You will get that when 1/2(theta) is 360
greatest value of sin is also 1. You will get that when 1/2(theta) is 90
Therefore plugging in 1 will give you 7 plus 5 plus 12 which is 24
Now 24 is the greatest value that occurs. For the smallest 'positive' however, you need a positive sign will the largest number i.e. 12 and a negative sign with 5 to get the smallest value. Therefore 1-5 12 will give you 14.
For less working you can even use your answer to part i and then determine cos and sin values
I repeat I'm not sure if that's correct. That was my mental calculation

I asked my friend answer, he also dont know but knows the direct answer, it is 585.2
and value is 20. Thats what he texted me. Not 24.