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yah...I've opted for S2 but I haven't started S2 yet...I'm still covering S1Is there anyone who has studied or opted S2 in Alevels ???? or maybe anyone studying or may have studied Advanced/high level Stats ???
You've got plenty of time. P1 is super easy. P3 is lengthy but you can do it. As far as M1 is concerned, you've studied physics so it'd be easy for you and S1, you should focus on permutations and combinations and probability. Rest all is pretty much formula-based and easyHave to give all four P1, P3, M1, S1 in May-June 2016.
You've got plenty of time. P1 is super easy. P3 is lengthy but you can do it. As far as M1 is concerned, you've studied physics so it'd be easy for you and S1, you should focus on permutations and combinations and probability. Rest all is pretty much formula-based and easy
You'd easily get an A*
yah...I've opted for S2 but I haven't started S2 yet...I'm still covering S1
I'm using this book :So do you know any book for S2 ??? or any solved book for its papers ???
could you please post the paper linkCan someone please solve the Q10 of W_14_33
It is the question of integration by substitution.
I integrated it but I am stuck at the limit and applying it.
Give me five minutes. Ill help you outView attachment 57660
How to solve this question please??? I'm completely lost
Give me five minutes. Ill help you out
Dm /dt = K(√M) cos (0.02t)View attachment 57660
How to solve this question please??? I'm completely lost
Inbox me all the questions you want done. Ill try my best to explainplease help me out with probability..it's really difficult to solve the complex ones..
Thankyou soooooooo much!!Dm /dt = K(√M) cos (0.02t)
dM / √m = kcos0.02t dt
ʃ dM / √m = ʃ kcos0.02t dt
(M ^(1/2)) / (1/2) = ksin0.02t/0.02 + c
Rearrange:
2√M =(ksin0.02t)/0.02 + C
Now we have t = 0 and M = 100 so just substitute inorder to find the constant C
Therefore,
2√100 = (ksin0.02(0))/0.02 + C
2(10) = 0 + C
C = 20
Now : substitute the value of C to find the relationship.
2√M = (ksin0.02t)/0.02 +20
**1/0.02 = 50
So, it will become: 2√M = 50ksin0.02t + 20
b) M = 196 and t = 50
Just plug in the values.
2√196 = 50ksin0.02(50) +20
14*2 = 50ksin0.02(50) + 20
28 = 50ksin0.02(50) + 20
28 – 20 = 50ksin0.02(50)
8 = 50ksin(1)
8/50 = ksin(1)
K = 0.19 Ans.
c) 2√M = 50ksin0.02t + 20
Make m the subject
You will get:
M = ((50ksin0.02t + 20)/2)^2
Plus in the values.
M =((50(0.19)sin0.02t + 20)/2)^2
Solve the square. And you will get around 27 or 28 as your answer
If you still have problem, Inbox me
I dont own a cellphone otherwise a picture wouldve cleared it out well. Sorry
No problem !! Im glad I helped!Thankyou soooooooo much!!
This is great! Your workings and steps are clear!!
Thanks a ton for your effort and time!!!
y = e^(-x) sinx
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