component of weight down the slope.Whats - 12500 (30/500) ?
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component of weight down the slope.Whats - 12500 (30/500) ?
component of weight down the slope.
component is mgsin(theta)I dont understand, how did you get that? :s
Ohhh, got it! thankyou so much!component is mgsin(theta)
mg is 12500
For sintheta, consider the triangle in the question. Length of the slope(500) is hypotenuse and the height(30) is the perpendicular. sin(theta) = 30/500
so the component is 12500(30/500)
Velocity after A is 10t - 0.15t^2 +C (Integrated acceleration)
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And ignore the top line of 2nd page
11 am (Saudi Arabia) (GMT + 3)What are the timings for your Mechanics exam?
Oh ok thanks! i was taking time as 0.5s instead of 0 :SVelocity after A is 10t - 0.15t^2 +C (Integrated acceleration)
This will be equal to 5 as at t=0 P is at A and that instant its velocity is 5ms-1.
So velocity after A is 10t - 0.5t^2 +5
Integrate this to get distance
5t^2 - 0.05t^3 + 5t
Time taken from O to A was 0.5s so after A will be 3.0s.
Put 2.5 in the equation to get 42.97 m after A.
Add 1.25 m from O to A. So total distance is 44.2 m.
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