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Mathematics: Post your doubts here!

TheJDOG

TheJDOG

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Debonny1 said:
View attachment 53151 Can someone please do part 1. Thanks
Click to expand...

Q6) I)First off, were told that perimeter of shade= 1/2 circle circumference
Find radius of shade by dropping down a perpendicular so you get this in terms of r and x. Also theta here will be 2x. Radius of shade we do cosx= Adj/r , hence adj = rcosx and so side AB= 2rcosx
Also side AC is 2rcosx
So Perimeter Shade= 1/2 Circle Circumference Get arc length = rtheta = 2rcosx 2x= 4rxcosx
Arc + AB + AC= 1/2 x 2pier
4rxcosx + 2rcosx + 2rcosx= pier
Cross r
4xcosx + 4cosx = pie Notice on left hand side cosx is a common factor

So cosx(4x + 4) = pie
Cosx= pie/(4x + 4)
X = cosinverse(pie/4x+4)
 
Aina

Aina

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TheJDOG said:
Q6) I)First off, were told that perimeter of shade= 1/2 circle circumference
Find radius of shade by dropping down a perpendicular so you get this in terms of r and x. Also theta here will be 2x. Radius of shade we do cosx= Adj/r , hence adj = rcosx and so side AB= 2rcosx
Also side AC is 2rcosx
So Perimeter Shade= 1/2 Circle Circumference Get arc length = rtheta = 2rcosx 2x= 4rxcosx
Arc + AB + AC= 1/2 x 2pier
4rxcosx + 2rcosx + 2rcosx= pier
Cross r
4xcosx + 4cosx = pie Notice on left hand side cosx is a common factor

So cosx(4x + 4) = pie
Cosx= pie/(4x + 4)
X = cosinverse(pie/4x+4)
Click to expand...
I took AB as rcosx..... plz explain
 
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