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Mathematics: Post your doubts here!

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DRM4eN.png

Rutzaba
sorry for the sloopy handwriting
 
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Last edited:
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https://files.cie.org.uk/tss/50630d...317/54330632/file/75/74475/S14_9709_qp_13.pdf

Can someone help me with Q7?
I am certainly sure that the answers of this particular question in the ms is wrong. So can someone please tell me the correct answer?
same prob here , dont knw how did they get the value for AB as 4i -2j 4k while i m getting -2i -2j 4k ???? i believe that the question is wrong ...
That's what we are discussing from yesterday. Question is wrong, position vector of b should be (6, -1, 7)
 
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View attachment 47850 View attachment 47849

Can anyone please solve this question for me?
i)
If Two Vector A and B are collinear (on the same line).. then Vector B = k(Vector A)

OA = (p, 1, 1) OB = (4, 2, p)

Comparing the j coefficents ..

OB = k(OA)
2 = k(1)
k=2

now compare either of the first or last to get p... Like comparing the first one we get

OB = k(OA)
OB = k(OA)
4= 2(p)
p=2 Answer

Unit vector in direction of OA vector :¬
As we know P = 2, hence, OA vector = (2, 1, 1)
So, 1/roof(2^2 + 1^2 + 1^2) = 1/root(6)


iii)
What you dont get in this? Simply do OB - OA.
 
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Tha
i)
If Two Vector A and B are collinear (on the same line).. then Vector B = k(Vector A)

OA = (p, 1, 1) OB = (4, 2, p)

Comparing the j coefficents ..

OB = k(OA)
2 = k(1)
k=2

now compare either of the first or last to get p... Like comparing the first one we get

OB = k(OA)
OB = k(OA)
4= 2(p)
p=2 Answer

Unit vector in direction of OA vector :¬
As we know P = 2, hence, OA vector = (2, 1, 1)
So, 1/roof(2^2 + 1^2 + 1^2) = 1/root(6)


iii)
What you dont get in this? Simply do OB - OA.

Thanks a ton!!
 
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