Mathematics: Post your doubts here!

[Awesome12]

M.Omar, what in the world have you just written there?

Maths

 

[M.Omar]

M.Omar, what in the world have you just written there?

D4 stuff

 

[F.Z.M. 7]

Allah khair,tha konsa mobile

BB Z10

 

[M.Omar]

Well bro, i got most of that figured out myself, h and k are turning points and they're 2,8 so i got that right.My main problem was in the g(x) functions.Could you solve that out on a page and post?

for the first image...for g(x) to be an iverse we need to define domain for either x>=2 or x=< 2 ...from the range in question in question i.e k=<x=<4 we see tht x=>2 nd thus k=2
...well the second image is self explanatory

 

[asadalam]

Thanks!

 

[Haya Ahmed]

Can someone prove this identity please ? :')
ZaqZainab

 

[RadzMau]

Hi, question 9 please!!!
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_12.pdf

 

[asadalam]

Hi, question 9 please!!!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf

What part dont you understand?

 

[JackAaron]

kindly solve 9709/33/O/N/12 qn 8. ii) ASAP

 

[Faaiz Haque]

Can someone help me with this question please and explain.
Q9ii) http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w06_qp_1.pdf

And
Q5)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w05_qp_1.pd

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w07_qp_2.pdf

Q3 (ii)

 

[Faaiz Haque]

I didn't attempt to do the sketch, though.

In part i i dont understand how you got to "a-b=7" when it should be "a+b=7"
explain please?

Thanks for replying btw,

 

[Anna Marie]

Can anybody please explain me question 3??
freeexampapers.com/index.php/directory/download?location=A%20Level/Maths/CIE/2002%20Nov/9709_w02_qp_5.pdf

 

[SitiPutri]

In part i i dont understand how you got to "a-b=7" when it should be "a+b=7"
explain please?

Thanks for replying btw,

Remember that cos 180 is -1. So a+bcos2(90) = a+bcos180 = a-b.

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_22.pdf

Q1 -- Why the answer is
-1<x<3
not
x>3 and x<-1 ???
isn't more than >0 means the second one ? .. why in ms there is range ?

 

[Thought blocker]

Heck lot things to type n m currently enjoying my vacations. Sorry for late but hope so I will be going home by October 3

 

[Thought blocker]

I am sorry, I didn't see that you already explained it. Whatever you wrote was correct and that's how argand diagrams are sketched. However, this guide is just for elaboration.

As Xtremepaper server isn't letting me upload the file in here, I've uploaded it on my dropbox account.
I hope this link works.
https://www.dropbox.com/s/9pdws1gqxo1b3yd/scan0007.pdf?m=

SalmanPakRocks any new guide

 

[exploded diper]

f(x) = 2x^2 - 12x + 13
f (x) = 2(x-3)^2 -5
for 0=< x =< A
state the value of A for which the graph of y=f(x) has a line of symmetry

 

[asadalam]

2 Find the set of values of k for which the line y = kx − 4 intersects the curve y = x2 − 2x at two distinct points. [4]

From s09p1.
I get we have to equate the answer and then use the discriminant but after getting 2 and -6 how do you know what each inequality we need to put?
Like the answer is k>2 and k<-6
How do we get this part right?

 

[Thought blocker]

f(x) = 2x^2 - 12x + 13
f (x) = 2(x-3)^2 -5
for 0=< x =< A
state the value of A for which the graph of y=f(x) has a line of symmetry

At x = 3 there is line of symmetry so A = x value so 1 is given zero and from 2(x-3)^2-5 we get A as 3 but we have 2 out the bracket hence A=6