Mathematics: Post your doubts here!

[Thought blocker]

Could you please explain the Range bit with some more detail please?
"− 2.5 ≤ x < 0"

Sure,
Put x as 1 in f(x) you get -2.5 as lower range

 

[Dudu]

Sure,
Put x as 1 in f(x) you get -2.5 as lower range

Right. I get that, but why do we put it in this format? -2.5<= x <0
Where did the 0 come from?

 

[Haya Ahmed]

On the same graph, draw the line y = -x/2 + pi
When x = 0 y = pie, when x = 3 y = 1.64 now connect both the points

how did you get y = -x/2 + pi .... we are supposed to get y = (pi-x)/2

 

[Thought blocker]

Right. I get that, but why do we put it in this format? -2.5<= x <0
Where did the 0 come from?

ZaqZainab

 

[Thought blocker]

how did you get y = -x/2 + pi .... we are supposed to get y = (pi-x)/2

Post the question's link.

 

[ZaqZainab]

ZaqZainab

which question?

 

[Thought blocker]

which question?

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_qp_12.pdf
question 9iii) How is the domain of f inverse has o ?

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w09_qp_11.pdf

Q2

Thought blocker

 

[Haya Ahmed]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_12.pdf
question 9iii) How is the domain of f inverse has o ?

Try substituting values for more than 1 and you'll find that the values of range keep decreasing till zero and it will never touch it and by knowing the graph of the function you will be able to relate what I'm saying

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_11.pdf

Q2

Thought blocker

My mistake.
So, put x = 0 and get y from the eqn, and put any other value of x and get your y, and plot the graph

 

[Haya Ahmed]

My mistake.
So, put x = 0 and get y from the eqn, and put any other value of x and get your y, and plot the graph

but we will get answers like 1.bla bla bla 0. bla bla bla .. how are we supposed to plot this on the graph there must be mistake somewhere plus the graph is not given in the ms so IDK WHAT TO DO

 

[Thought blocker]

but we will get answers like 1.bla bla bla 0. bla bla bla .. how are we supposed to plot this on the graph there must be mistake somewhere plus the graph is not given in the ms so IDK WHAT TO DO

Take very far points on x axis and connect 'em

 

[Faithix MFSH]

Can someone solve this?

I solved part (i) easily and part (ii) doesn't depend on part (i) so let it go.
Now in part (ii) I was able to draw the circle with centre i and radius 1. I just wasn't able to draw a locus with angle 3/4 pi to the real axis.

Can someone help me draw the locus and complete the solution of the question?

Thanks in advance,

 

[Talha Khatri]

Phew, that took a while to write clearly and illustrating properly sorry for the delay

 

[Haya Ahmed]

Take very far points on x axis and connect 'em

omg are you serious ? .. since when do we get these kind of decimals .. ABNORMAL decimals !!

 

[Thought blocker]

omg are you serious ? .. since when do we get these kind of decimals .. ABNORMAL decimals !!

Its the only way I do it, if you get more accurate way, do tell me

 

[princeali97]

?

What? this is the formula

 

[Faithix MFSH]

Phew, that took a while to write clearly and illustrating properly sorry for the delay
View attachment 41014 View attachment 41015 View attachment 41016

Okay I just saw this so Im gonna try it now, but either way, whether it makes sense or not;
Thank you very much for working it out.

 

[Thought blocker]

What? this is the formula

Ikr.

 

[Haya Ahmed]

I dont know this method is correct or not
We had to show a point of reflection, hence we have x1,y1 as (-1,3) and we found a midpoint (3,9) by sim. equation,
So, as to find midpoint we do (x1+x2)/2, and (y1+y1)/2,
similarly,
We know have to find x2 and y2, we have x1 y1 and midpoint
so (x1,y1, + x2,y2)/2 = midpoints
=(-1,3 + x2,y2) = 2(3,9)
=(-1,3 + x2,y2) = (6,18)
x2=(6-(-1))=7
y2=(18-3)=15

so reflection on (7,15)


T H I S R E A L L Y W O R K S


Yes I nees work solution on question 8

How did you get 3,9 ?