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No brother i i was asking for the last part i.e (iv) . :/Put y as zero, so ; 0 = x(x-2)^2 => 0 = x^3 - 4x^2 + 4x + 0, you will find that you get two roots by solving this, one root will be 2 and second will be zero, and from graph, clearly it is seen x is not zero so x is 2, hence a = 2