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Mathematics: Post your doubts here!

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I dont find anything "degrading on this intellectual forum".But anyways i dont bother all this.Nice explanation :) .But my question is that the gradient of tangent and curve will be the same at that point ryt?.So how are u supposed to find the angle my friend?
LOL I am not even going to bother explaining this now, just re read what I explained, it is very clear. I'm talking about two different points here.
 
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I dont understand the last step, the one right before the final answer..
How does the denominator finalize to become 1? I know that the numerator is the answer we're trying to reach, okay. But the denominator should be 1, now how does 1 + (tant) (tan 1/4pi) equate to 1? (tan 1/4pi) is equal to 1 not zero, so how did tant get cancelled off? Shouldn't it be, tant - (tan 1/4pi) / (tan 1/4pi) + tant ?
I don't think it's possible to substitute 1 with (tan 1/4pi) only in the numerator..

Please do explain.
I think you are forgetting the fact that tan (A-B) = (tan A - tan B) / (1+(tanA)*(tanB))
so the denominator was 1+tan t right?
so we can write this as 1+ (tant *1)
and now 1 = tan 0.25pi and we can substitute this without causing any problems to our equation :p
and this can be turned into tan (t-0.25pi)
 
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