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Suchal Riaz
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??Need help with the circled questions..
Part 2 .Lil Confuse . Please do the solution on paper and post the snapshot here.
and Part 3
Suchal Riaz
I uploaded the picture after a minute or so..
Did you open the bracket when differetiating ? you should do that !View attachment 39978
the thing that's confusing me here is that after differentiating we get t=100 ...
isn't t=100 the time at which the speed is max?
in the ms they have considered it to be the the time taken for the distance AB travelled.... it's confusing me to bits!!:/
and umm well solve the rest of the questoin too if u can
I uploaded the picture after a minute or so..
yeah i did get the right answer... it was t=100Did you open the bracket when differetiating ? you should do that !
when you do a complex no question its doubledthat amazing moment when you do a p3 question correctly :')
Praise the Lord...! :')when you do a complex no question its doubled
for me it would be differential equation or vectors or trig quesitonwhen you do a complex no question its doubled
rearrange the equation such that it is in the form:
when we differtiate equation we get Velocity equationyeah i did get the right answer... it was t=100
what i'm asking is that is t=100 the time when the particle reaches B??
shouldn't 100 be the time when the speed is max??
X^2 + 5X = 8 in the form of (ax^2 +bx) +Crearrange the equation such that it is in the form:
lny = lnA - kx^2
-->
lny = -kx^2 + lnA
from this u can see that ur gradient will be -k and ur y-intercept is lnA
find the gradient using the coordinates of the two given points and equate it to -k .... then put in the values of lny , k, and x^2 from one of the points in the equation and find c i.e. lnA
got it?
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