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Mathematics: Post your doubts here!

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i need help for paper 32 may/june 2013 plzz question 10
plzzz i have an exam 2morrow
 
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The points A and B have position vectors 2i − 3j + 2k and 5i − 2j + k respectively. The plane p has
equation x + y = 5.
(i) Find the position vector of the point of intersection of the line through A and B and the plane p.
(ii) A second plane q has an equation of the form x + by + cÏ = d, where b, c and d are constants.
The plane q contains the line AB, and the acute angle between the planes p and q is 60Å. Find
the equation of q.


this is the question..
 

Tkp

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can some1 help me in may june 12 (32) ques 5
 

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can some1 help me in may june 12 (32) ques 5
dy/dx= e^(2x+y) = e^(2x) * e^y
e^(-y) dy = e^(2x) dx
-e^(-y) = 0.5e^(2x) + c
substitute x=0 y=0
-1 = 0.5 + c c= -1.5
-e^(-y) = 0.5e^(2x) - 1.5
e^(-y) = -0.5e^(2x) + 1.5
-y = ln(3-e^(2x)/2)
y = ln(2/(3-e^(2x))
 
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Tkp

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dy/dx= e^(2x+y) = e^(2x) * e^y
e^(-y) dy = e^(2x) dx
-e^(-y) = 0.5e^(2x) + c
substitute x=0 y=0
-1 = 0.5 + c c= -1.5
-e^(-y) = 0.5e^(2x) - 1.5
e^(-y) = -0.5e^(2x) + 1.5
-y = ln(3-e^(2x)/2)
y = ln(2/(3-e^(2x))
thnks
 

Maz

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Hey, could someone please post notes for complex numbers and vectors. Especially complex- i'm more or less lost... Please...:(
 
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Hello can anyone solve this maths for me.... June 12/p32 Question no. 2 (ii) .... Please help me......
 

Maz

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Hello can anyone solve this maths for me.... June 12/p32 Question no. 2 (ii) .... Please help me......
Take f(x) = ø - tan^-1(3ø)

Search for a sign change.
f(0) = 0
f(pi/4) = -0.38
f(pi/2) = 0.21

Therefore, the root is between pi/4 and pi/2...
take x1 = pi/4...
I guess now it's easy...
 
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