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Mathematics: Post your doubts here!

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Dude, just multiply your two answers from part i) to get one quadratic factor and find the other one by (Ax^2 + Bx + C) inspection.
That is, the roots you get in i) are 1 - √2 i and 1 + √2 i. So the factors become (x-1+√2 i)(x-1-√2 i). You multiply the brackets and you'll see everything in terms of 'i' gets cancelled to give you a quadratic factor of x^2 - 2x +3.

If you still don't get it, let me know I'll post a screenshot.
I get! Thanks a lot man! :)
 
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Hey, you switched your axis! You put the imaginary one in the real one!
OMGG THAT EXPLAINS IT ALL!!
When I add ninety degrees because now the Angle is in the second quadrant I get the right answer! Thanks!!
 
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InshaAllah :)

What's driving me insane is, what in the world were they thinking sticking maths and chemistry in one day? And Stats and physics p4 two days later? They're HUGE papers- it's like they WANT us to do bad.

This meme makes SO much sense now:
3r7et2.jpg
 
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What's driving me insane is, what in the world were they thinking sticking maths and chemistry in one day? And Stats and physics p4 two days later? They're HUGE papers- it's like they WANT us to do bad.

This meme makes SO much sense now:
3r7et2.jpg
I KNOW RITE !!!
i am sleep deprived :p
you know CIE ! always in the torturing mood xD
its like they get peace when they see us in pain xD
 
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i have a feeling a question of this type is coming tomorrow..pls can someone fully explain it question 10 second part

this is functions bro ....
P(x) = x^2 + 2x +3
P(1) = 1 + 2 + 3 = 6
p(x^2) = (x^2)^2 + 2 (x^2) + 3


now try to do that question
hope yu get it . ....
 
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The paper being too hard is not so good sometimes !
Because in the exam hall, you might get confused and you are stressed ! Then, you start messing around ! :s
yeah ik but being so easy is the worst because i am one of these dudes who can make so many silly mistakes because of exam stress lol
 
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this is functions bro ....
P(x) = x^2 + 2x +3
P(1) = 1 + 2 + 3 = 6
p(x^2) = (x^2)^2 + 2 (x^2) + 3


now try to do that question
hope yu get it . ....
no bro i didn't get it :/ can u show the solution of this question..only the last part pls
 
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yeah ik but being so easy is the worst because i am one of these dudes who can make so many silly mistakes because of exam stress lol
Agreed ! same here !
Lets hope the paper gonna be average, Insha Allah ! :)
 
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Hi all, I would please like to know the solution of question 4 in this paper. I just reached that point where I should leave the question or I will cause myself problem. Thanks in advance :)
cosec2@ = sec@ + cot @
so,
1/sin2@ =(1/cos@) + (cos@/sin@)
1/sin2@ = (sin@ + cos^2@)/(cos@sin@)
1/sin2@ = [sin@ +(1- sin^2@)]/ (cos@sin@)
1/sin2@ = (sin@+1- sin^2@)/(cos@sin@)
i am multiplying right hand side with (2/2) so,

1/sin2@ = 2(sin@+1-sin^2@)/2sin@cos@
1/sin2@ = 2(sin@+1-sin^2@) / sin2@
sin2@ gets cancelled out therefore we are left with:
1 = 2(sin@+1-sin^2@)
1 = 2sin@ +2 - 2sin^2@
2sin^2@ - 2sin@ -1 = 0
now u can find the angle (y)
 
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