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well they both started from rest with same conditions (driving force resistance etc...)how did you know that the both particles have same acceleration?
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well they both started from rest with same conditions (driving force resistance etc...)how did you know that the both particles have same acceleration?
i like how you emphasized that it was paper 3 xDCIE Puremath3: Some help here please!Please help me with 9709/paper 33 year:October/November 2012 question 10 b (ii). Please help badly stuck with it! Thank youLink to Question: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf
what year is this? pls when posting question post the paper so i can check the mark scheme after solving it to make sure i am not giving u the wrong answer!
sorry for the delay but here you go:http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w06_qp_4.pdf
Pie-man
or anyone ....... how to do 7(iii) ?
Thank you
i like how you emphasized that it was paper 3 xD
the people that take paper 3 in this forum (of which i know about) will be online soon so solve more equations until then. good luck
how did you know that the both particles have same acceleration?
@iKhaled
Cud u help wid this...
9709/paper 33 year:October/November 2012 question 10 b (ii). Please help badly stuck with it! Thank you
Link to Question: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf
Link to Mark Scheme: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_33.pdf
Thank you
The values of mod Z is a line through the origin passing through the centre of the circle.So the greatest and least values of mod z is the length that corresponds to the two points that the line touches the circle with.and since the diameter is four,you know that the greatest mod is four more than the vaule for the min mod Z@iKhaled
Cud u help wid this...
9709/paper 33 year:October/November 2012 question 10 b (ii). Please help badly stuck with it! Thank you
Link to Question: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf
Link to Mark Scheme: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_ms_33.pdf
Thank you
yes!!!....they are correct!!!.........sorry for not posting the year or the answer...........thanks a lot!!...I have solved it... uploading in few min... but first do u knw the answers? are they
i. 3x-4y+6z=80
ii.30.81
Uploadin the full procedure will take some tym just w8!
The values of mod Z is a line through the origin passing through the centre of the circle.So the greatest and least values of mod z is the length that corresponds to the two points that the line touches the circle with.and since the diameter is four,you know that the greatest mod is four more than the vaule for the min mod Z
Hope this helps you.
Mention not!its ok!yes!!!....they are correct!!!.........sorry for not posting the year or the answer...........thanks a lot!!...
THANKS A LOT!!!!....Here is the answer:
Direction of plane=n= direction of line
n=(a b c)
Direction of line:
AB⃗ =OB⃗-OA⃗
=r⃗ .n⃗ =a⃗ .n⃗
=(2 -2 11)-(-1 2 5)
=(3 -4 6)
= (a b c)
Therefore equation of plane= 3x-4y+6z=d
Let r= (x y z) and n=(3 -4 6)
Therefore, (x y z). (3 -4 6)=(2 -2 11).(3 -3 4)
ð 3x-4y+6z= 6+8+66=80
Now Solution to part 2:
At y axis xand z is equal to zero
Therefore, Subsituting values In the plane equation:
We get… 4y=80
ð y=20
Now using dot product, we have…
(0 20 0).(3 -4 6)= |(0 20 0)|.|(3 -4 6)|.cosO
=> -80=(Ö202).(Ö32+42+62) .cos0
=> cosO= -80/(20Ö61)
Or a=cos-1(80/(20Ö61))=59.193 o (Look that – sign has been ignored)
As there is a minus sign so we have to consider 2nd quadrant (Remember Trigonometry! ; ))
so we get,O=120.807 o
NowOis the angle between the normal of plane and y
To get require angle we need to subtract 90o from it n so we have
the angle=30.81
Hope it helped!
Sorry.. i'll keep this in mind next time....what year is this? pls when posting question post the paper so i can check the mark scheme after solving it to make sure i am not giving u the wrong answer!
Mention not!THANKS A LOT!!!!....
Hey tried solving it bt cnt! Sorryhelp guys in solving this .. (2x-1)ln5=ln2 + xln3 .. i have difficulities in this sort of questions
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