Mathematics: Post your doubts here!

[Gémeaux]

Aoa, just a small doubt in Q10 (b) (ii), if someone could please tell how to do this one.
It's a one-mark question.
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s12_qp_33.pdf
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_ms_33.pdf
I'd be really grateful.

 

[TaffsAsLevel]

Aoa, just a small doubt in Q10 (b) (ii), if someone could please tell how to do this one.
It's a one-mark question.
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s12_qp_33.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_ms_33.pdf
I'd be really grateful.

Hey, here's the solution
http://t.co/ZDzl0Yh9cE

http://t.co/T23uUZNZmC

 

[TaffsAsLevel]

Aoa, just a small doubt in Q10 (b) (ii), if someone could please tell how to do this one.
It's a one-mark question.
http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s12_qp_33.pdf
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_ms_33.pdf
I'd be really grateful.

Btw do you know how to upload pictures rather than giving the url?

 

[TaffsAsLevel]

Anybody can help me with this? I got all correct till the exact end I got wrong. Please help

http://postimg.org/image/p18toco3f/

http://postimg.org/image/or1b509h7/

 

[Gémeaux]

Hey, here's the solution
http://t.co/ZDzl0Yh9cE

http://t.co/T23uUZNZmC

Thankyou but I don't get why you wrote under root of 1^2 + 1^2.

 

[TaffsAsLevel]

Thankyou but I don't get why you wrote under root of 1^2 + 1^2.

Pythagoras theorem

 

[Gémeaux]

Btw do you know how to upload pictures rather than giving the url?

Yeah if you want to upload a picture from your computer, there is button on the right besides *Post Reply* for that. Other wise you could also insert and image by pasting it's URL in the box that appears when you click this tree sort of image above that reads Insert/edit image.

 

[Gémeaux]

Pythagoras theorem

Oh I get it! Thankyou so much.

 

[TaffsAsLevel]

Oh I get it! Thankyou so much.

ooooops sorry for the other picture I gave you was for Nov 2012, really sorry

 

[TaffsAsLevel]

Yeah if you want to upload a picture from your computer, there is button on the right besides *Post Reply* for that. Other wise you could also insert and image by pasting it's URL in the box that appears when you click this tree sort of image above that reads Insert/edit image.

Ohh thank you

 

[TaffsAsLevel]

Any one can solve this for me?

 

[Gémeaux]

ooooops sorry for the other picture I gave you was for Nov 2012, really sorry

Not a problem. Not so dumb after all to try putting this into what I asked

Ohh thank you

You're welcome

 

[Gémeaux]

Any one can solve this for me?

You were doing it right, but your answer's incomplete yet.
After what you did, use equations from y and z simultaneously to find s and t.
-1+s = 2+t 4-s = 1+t
-1 +s = 2+3-s <-- t = 3-s
s= 3
this gives t = 3-3 = 0. This is different from what the previous two equations gave, hence the lines do not intersect.
(Had the been intersecting, you'd get s and t from both comparisons same.)

 

[TaffsAsLevel]

You were doing it right, but your answer's incomplete yet.
After what you did, use equations from y and z simultaneously to find s and t.
-1+s = 2+t 4-s = 1+t
-1 +s = 2+3-s <-- t = 3-s
s= 3
this gives t = 3-3 = 0. This is different from what the previous two equations gave, hence the lines do not intersect.
(Had the been intersecting, you'd get s and t from both comparisons same.)

Are you sure? Because mark scheme said all three component should not be satisfied. =/

 

[Esme]

the fastest way is to use lami's rule to get the angle opposite to P1 then get the angle AP1X using subtraction from 360 degrees, then lami again to get the value of W.

Sorry to bother you but can you please solve it for me ? I didn't get you..

 

[Esme]

Are you sure? Because mark scheme said all three component should not be satisfied. =/

Yep that explanation's correct

 

[50sum]

Question 5) no 2 , can you explain the work energy principle here? I dont understand why the work done against friction is negative, and why the ke loss is greater than the pe gain? How do I figure out when the loss is greater than the gain to be precise.

 

[Esme]

Question 5) no 2 , can you explain the work energy principle here? I dont understand why the work done against friction is negative, and why the ke loss is greater than the pe gain? How do I figure out when the loss is greater than the gain to be precise.

There was a loss in KE because the speed decreased from 3 to 0. And there was a gain in PE because it moved from a lower point to a point of greater height. What I did for this question was:
Work done by driving force is 0.
Work done by driving force= Gain in PE + Work done against resistance - Loss in in KE.
(Whenever there's a gain we add and when there's a loss we subtract. This above formula always works for me)
0= PE + 0.39 - 1.35.
PE= 1.35-0.39= 0.96
mgh=0.96
0.3x10xh=0.96
h=0.32

 

[syed1995]

ok guys heres the deal
6 ii 5 students sit anywhere by the window... 5! =120
3 business men sit anywhere= 3!= 6
now for the married couples... there are 2 couples =2 two seats each =2 and 3 seats remaining for each couple =3p2
3p2 *2*2= 24
5!=120
3!=6

24*6*120 = 17280

Somethings of this question which bother me. There are 9 window seats total. 1 Occupied by Business guy.. so 8 left.

3 of those remaining seats coincide with those where the couples might sit.. So what about that? What we're doing here is just making sense of the mark scheme.. but if you take it practically then that would be wrong.. to not consider the two points which I mentioned.

 

[InternationationalGuy]

Guys. can anyone please tell me or give me some links that can help me in p4 mechanics 1. Thanks. May Allah Grant everyone great Grades In Sha Allah.