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ok just see the diagram carefully.the object is in equilbrium.so the frictional force must be opposite to 6.1 N.Please anyone could explain to me mechanics /jun11 variant 43 no.4 and no.5 urgently ?
so to find the frictional force 6.1+5costheta(as the theta is in the x axis)=f,so f is 7.5
u=f/r(r is mg as the object is in equilbrium)
3rd 1 is same as 1st 1.now the 6.1 is replaced with 8.6n.so 8.6+5c0stheta-f=ma
and the accleration must be in left direction as the object is moving