Mathematics: Post your doubts here!

[Vinita Manek]

can anyone help me with qt 2 from 9709/07/o/n/07

 

[xyz!]

what was the perpendicular height??

i got 6.33 ....did u get dat?

 

[shanky631]

i got 6.33 ....did u get dat?

ya.. something like that

 

[kevin94]

3 A sample of 36 data values, x, gave Σ(x − 45) = −148 and Σ(x − 45)2 = 3089.
(i) Find the mean and standard deviation of the 36 values. [3]
(ii) One extra data value of 29 was added to the sample. Find the standard deviation of all 37 values.

how to do the second part?

 

[TeKnOzOr]

32???

yAa variant 32 man...and you?!?

 

[emkay]

okay, so do you guys think its possible for one to appear for complete A'level mathematics including P1,P3,M1 and S1 in mayjune with only 6months in hand while he has to appear for A2 phy and computing too?

 

[momo_khan]

can any one help me with question 6 part 2 from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_61.pdf

question 2 from -----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_62.pdf

question 2 and question 6 part two from ----> http://olevel.sourceforge.net/papers/9709/9709_s12_qp_63.pdf

does anyone have some good notes for statistics ?

whitecorp

@everyone

 

[RockyBo1234]

Hello guys
Can anyone help me with this:-
statistics 2
whitecorp
bamteck
minato112
@everyone

 

[RockyBo1234]

One more friend!!in stats 2
whitecorp
shanky631
john10
@everyone again!

 

[Vinita Manek]

Hello guys
Can anyone help me with this:-
statistics 2
whitecorp
bamteck
minato112
@everyone
View attachment 17752

add d sum of d probabilities of 0 and 1.....dat will be equal to 0.01 i.e 10 % or less than dat...wen u add d probablitity of 2...it becomes higher...thus ur rejection region is 0 n 1.....

 

[Vinita Manek]

One more friend!!in stats 2
whitecorp
shanky631
john10
@everyone again!View attachment 17755

but here the actual mu is already given..u use continuity correction when u have found the mean yourself....

 

[RockyBo1234]

add d sum of d probabilities of 0 and 1.....dat will be equal to 0.01 i.e 10 % or less than dat...wen u add d probablitity of 2...it becomes higher...thus ur rejection region is 0 n 1.....

Hey I got that so they allow both 0 and 1!!cool

 

[RockyBo1234]

but here the actual mu is already given..u use continuity correction when u have found the mean yourself....

I disagree!!Whenever u convert from poisson to normal u definitely use cc!!

 

[RockyBo1234]

but here the actual mu is already given..u use continuity correction when u have found the mean yourself....

hey can u elaborate more and be precise!!i may then get it!

 

[momo_khan]

question 5 and 7 from -------> http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_61.pdf

question 6 from -----> http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_62.pdf

question 2part 1 , 6 from -----> http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_63.pdf

question 3 part 3 from -----> http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_61.pdf

question 5 part 2 and 3 from ----> http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_62.pdf

thanks in advance.
can anyone lend me their statistics (p6) notes ??

whitecorp yashi30
@everyone​

 

[snowbrood]

help people

 

[Vinita Manek]

when u use nd to approx bd u need a cc of +- 0.5.....dat is becuse in binomial distribution u r gvin the probabilty of success and n....here u multiply both n u find ur own mean....also v approximate variance by npq....since frm bd v r usin nd v use +- 0.5....

 

[DumbIdiot]

Could someone please explain what is done in Q3 (ii), I don't understand what is done in the ms

 

[athaan]

Can someone help me with question number 6(iii) in ON2010 P63 ASAP? -- http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w10_qp_63.pdf

I tried looking for an explanation but couldn't find one. I'm sorry if this question has been asked and answered. I don't understand why the students is 5 -- or 5/12.

 

[athaan]

Could someone please explain what is done in Q3 (ii), I don't understand what is done in the ms

this is how I did my work, hope it clears your problem!

You're asked to find how many 'n' is needed, for P(X>=1) > 0.95
Success is obtained when a person rated 'poor', so p = 0.13
Therefore, it wouldn't be a success if the person rate else than 'poor', so q = 0.87

0.95 < P(X>=1)
---P(X>=1) = 1 - P(X=0)----
0.95 < 1 - P(X=0)
0.05 > P(X=0)

P(X=0) = nC0*0.87^n
P(X=0) = 0.87^n
----since nC0 = 1, we can eliminate it from the equation----

therefore,
0.05 > 0.87^n

use logarithm to find out 'n'. I found it 21.5.
if n = 21, then it wouldn't be 0.95 < P(X>=1)
if n =22, the statement 0.95 < P(X>=1) will be true.

So, the answer is 22.