Mathematics: Post your doubts here!

[john10]

View attachment 17449

From where did u get the initial value??

 

[whitecorp]

Can anyone help me in this question?
10)ii)b)
View attachment 17447



Answer:
View attachment 17448

Previously solved 10(i) here, for your reference first:

Solutions for 10(i)

Hope this helps. Peace.

 

[whitecorp]

Thanks sir!

You are most welcome. Peace.

 

[Kirabo Takirambudde]

Guys which answer is correct???

 

[whitecorp]

Hi guys
Can you help me with these parts, a few lines for each question will be much appreciated.
View attachment 17435
leadingguy whitecorp parthrocks shanky631

Full solutions for vectors problem 6(i) and (ii) here:



Hope this helps. Peace.

 

[whitecorp]

Guys which answer is correct???View attachment 17451View attachment 17452View attachment 17453

Both are wrong. Peace.

 

[junyl93]

The full solutions for this vectors problem here:



Hope it helps. Peace.

Excuse me sir, but for (iii), how do u know point A is (5,0,0) ?? Why AB times (unit vector 2,-2,1) ??? Why use unit vector? Please do tell me.

 

[whitecorp]

Excuse me sir, but for (iii), how do u know point A is (5,0,0) ?? Why AB times (unit vector 2,-2,1) ??? Why use unit vector? Please do tell me.

Because the scalar product of (5, 0, 0) and the normal to the plane (2, -2, -1) equals 10, hence the point (5, 0, 0) lies on the plane. You can always choose another point if you want to, so long as the scalar product of that point and the normal to the plane equals 10. For example you could use ( 0, -5, 0).

With regards to AB dot unit vector of ( 2,-2,1), this uses the concept of projection vectors, and in this instance, the projection of the vector AB onto the normal of the plane.

Hope this helps. Peace.

 

[bamteck]

ln(1+y²) =2 x + 1/ln5

1+y²= e^ (2 x + 1/ln5)

y²= e^ (2 x + 1/ln5) -1 (shown)

Hope this helps. Peace.

Why the marking scheme quote the answer as : y² = 5 e2x - 1 ?

 

[shanky631]

Plz help guys.
whitecorp
parthrocks
leadingguy

 

[junyl93]

With regards to AB dot unit vector of ( 2,-2,1), this uses the concept of projection vectors, and in this instance, the projection of the vector AB onto the normal of the plane.

Hope this helps. Peace.[/quote]


Okay....i kinda get it now about the projection stuff. Thanks alot sir. If u have time, can u help me with ques 10(iii) and 6(i). Here

 

[RockyBo1234]

U mean the term "non-zero"?

ya!

 

[RockyBo1234]

help someone

 

[momo_khan]

white corp can you kindly solve the vectors question from may june 2012 paper 32 .

 

[Kirabo Takirambudde]

View attachment 17341


Does anybody have the workings to (bii) of this question???

 

[Mattman]

Guys, http://www.xtremepapers.com/papers/...AS Level/Mathematics (9709)/9709_w08_qp_3.pdf


number 10 please.

 

[Kirabo Takirambudde]

Guys, http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w08_qp_3.pdf


number 10 please.

which part??

 

[xyz!]

can sum1 help me wid the q.10)b)ii) pls ??

 

[xyz!]

Q.8)ii) pls!

 

[xyz!]

whitecorp sir pls help me out with q.6)ii) and also with 2 doubts dat i hav posted above...pls!