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Mathematics: Post your doubts here!

M

Munk Bro

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heyy guys, does anyone whether there is any pattern for AS level P1 papers n the past years... I'm doing P12... Please help me out if anyone knows.. please....
 
whitecorp

whitecorp

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NokiaN95638 said:
Help on P2 questions needed!!! (here @= theta)
Q. The Parametric equation of a curve are
X=2@+cos@ y= @+sin@

0≤@≤2π


1. Find dy/dx in terms of @. (no problem on this one)
2. Show that, at points on the curve where the gradient is 3/4 the parameter @ satisfies an equation of the form:
5sin(@+α)=2 , where the value of α is to be stated.
3. Solve the equation in part(ii) to find 2 possible values of @.
Click to expand...


Here are the full solutions.





You may wish to take note that (ii) uses the R-formula; you can refer to this piece I written on my supplementary site:
http://www.msharpener.com/2012/09/trigonometric-formulae-2.html

Hope this helps. Peace.
 
Soldier313

Soldier313

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whitecorp and others
need some help here integrating:
find the volume of the solid formed when the graph of y = (1/x*2) between x=1 and x=2 is rotated about the x - axis.
answer is: 2 Π ln2
 
whitecorp

whitecorp

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Soldier313 said:
whitecorp and others
need some help here integrating:
find the volume of the solid formed when the graph of y = (1/x*2) between x=1 and x=2 is rotated about the x - axis.
answer is: 2 Π ln2
Click to expand...

Is that y=1/(x^2) ? Because if it is then I am positive the answer you provided is incorrect.
 
Soldier313

Soldier313

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whitecorp said:
Is that y=1/(x^2) ? Because if it is then I am positive the answer you provided is incorrect.
Click to expand...
yes it is.....the textbook says the answer is 2.pi.ln2....what answer did you get...and how did you arrive at it? the textbook might be wrong
 
whitecorp

whitecorp

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Taiyaba said:
whitecorp plz help me with second one :(
Click to expand...

The series 1+3+5+...........+(2n-1) constitutes an arithmetic progression (AP) that has n terms in all, first term of value 1 and common difference =2.
Then we can simply use formula for sum to n terms, which is given by (number of terms divided by 2)*(sum of first term and last term)
=n/2 * (1+2n-1) = n/2 * (2n) =n^2 (shown)

Hope this helps. Peace.
 
Taiyaba

Taiyaba

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whitecorp said:
The series 1+3+5+...........+(2n-1) constitutes an arithmetic progression (AP) that has n terms in all, first term of value 1 and common difference =2.
Then we can simply use formula for sum to n terms, which is given by (number of terms divided by 2)*(sum of first term and last term)
=n/2 * (1+2n-1) = n/2 * (2n) =n^2 (shown)

Hope this helps. Peace.
Click to expand...
Thnx :) bt hw do v show that it is always a perfect square?
 
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