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Mathematics: Post your doubts here!
- Thread starter XPFMember
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You are the best!!! yay I get it now!
- Messages
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- 419
- Points
- 73
- Messages
- 500
- Reaction score
- 419
- Points
- 73
what's the year of this question?
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Printing error.
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Using Work Energy Principle,
1. Let the starting point be A and the end point be C.
2. List down Energies and Work at point A and C
Point A:
Ep = 0 J
Ek = 1/2 × 840 × 14^2 = 82320 J
Work done against resistive force = 0 J
Point B:
Height from the ground = 8sin30 - 10sin20 = 0.58m
Ep = 840 × 10 × 0.58 = 4872 J
Ek = 1/2 × 840 × v^2
Work done against resistive force = from part i we got it as 11520 J
3. Use the work - energy equation and solve for v
Point A = Point B
82320 = 4872 + 420v^2 + 11520
Thus, v = 12.5 m/s (3sf)
HI guys, so I wrote my AS level pure math 1 paper today and it was easy but I couldn't get a 6 marks question right :'((
they gave: y= [(x^3+x^2)]^0.5
and in the question, the very first thing we had to do was differentiate it. Now I'm usually good at differentiation. I can do the product rule, quotient rule and chain rule even. However I had this assumption, god knows why that in AS level at least, we can only apply the chain rule for linear equations. Then this question suddenly comes up and messes my whole grade up. I've searched and people use substitution method which is A level. Have you guys learnt this level of differentiation in your AS level too? or was it just me who didn't know?
they gave: y= [(x^3+x^2)]^0.5
and in the question, the very first thing we had to do was differentiate it. Now I'm usually good at differentiation. I can do the product rule, quotient rule and chain rule even. However I had this assumption, god knows why that in AS level at least, we can only apply the chain rule for linear equations. Then this question suddenly comes up and messes my whole grade up. I've searched and people use substitution method which is A level. Have you guys learnt this level of differentiation in your AS level too? or was it just me who didn't know?
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Sorry to hear that but you can differentiate it directly
Dy/dx=3x^3/[x^3+x^2]^0.5
We use quotient rule when we divide two different functions e.g x/x^2
We use product rule when we multiply two different functions e.g 3x.Cosx
We use chain rule when we three variables e.g x, y, t
Dy/Dx=Dy/Dt x Dt/dx.
Btw in differentiation we can differentiate linear or non linear equations.
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Yes, I rechecked with my teacher too. The real fact was that you can only apply the chain rule to a linear equation while integrating. Stupid, stupid mistake.
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This could be done with chain rule
I know now
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