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It's the expansion of any of the roots and simplifying itThanku,so basically its expansion of any of the conjugates??
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It's the expansion of any of the roots and simplifying itThanku,so basically its expansion of any of the conjugates??
please explain how to eliminate y from last step to get answer for x in terms of aIt's the expansion of any of the roots and simplifying it
please explain how to eliminate y from last step to get answer for x in terms of a
i) The function is made up of 2 parts: Curve + Straight line. The domain is given for both parts and the resulting graph is said to be of f(x). So if we look at the graph we know the max and min x-values. They are given in the domains in the question. Max x-value is 4 and Min x-value is -1.PLZ HELP
Hey guys, can anyone help me out with Q3 (i)? Thank you!
How did you shorten it to become 9x^2-6x?Shorten it to
=9x^2-6x
=3x^2-2x
=(3x-2)^2 +1
How did you shorten it to become 9x^2-6x?
i think if we divided the 12x we must divide the whole equation by 2Divide the 12x by 2
http://maxpapers.com/wp-content/uploads/2012/11/9709_s13_qp_32.pdfCan you show me the question? I remember I have solved this question before, there is a way to do the last step
Thanks A LOT >>> really helpful !i) The function is made up of 2 parts: Curve + Straight line. The domain is given for both parts and the resulting graph is said to be of f(x). So if we look at the graph we know the max and min x-values. They are given in the domains in the question. Max x-value is 4 and Min x-value is -1.
Now the top part is the curve so we put x-value 4 in the curve equation to get the max y-value and the x-value -1 in the straight line equation to get the minimum y-value and that is the range.
ii) I hope you can find the inverses. They are easy. Here is the graph:
Dotted lines are from the inverse functions.
please explain me q in this paper too ,q7 part2Can you show me the question? I remember I have solved this question before, there is a way to do the last step
y^2=6ax-3x^2
Go here: http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/P1/module.phphow to know if a function will have inverse or not ..and how to find minimum value for it to be inverse
Ahh I'm late, sorry I just arrived, what Ahmad said is true
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