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Mathematics: Post your doubts here!

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where? i forgot :/
I dont know this method is correct or not :p
We had to show a point of reflection, hence we have x1,y1 as (-1,3) and we found a midpoint (3,9) by sim. equation,
So, as to find midpoint we do (x1+x2)/2, and (y1+y1)/2,
similarly,
We know have to find x2 and y2, we have x1 y1 and midpoint :)
so (x1,y1, + x2,y2)/2 = midpoints
=(-1,3 + x2,y2) = 2(3,9)
=(-1,3 + x2,y2) = (6,18)
x2=(6-(-1))=7
y2=(18-3)=15

so reflection on (7,15)


T H I S R E A L L Y W O R K S :)


Got it ? o_O
 
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I dont know this method is correct or not :p
We had to show a point of reflection, hence we have x1,y1 as (-1,3) and we found a midpoint (3,9) by sim. equation,
So, as to find midpoint we do (x1+x2)/2, and (y1+y1)/2,
similarly,
We know have to find x2 and y2, we have x1 y1 and midpoint :)
so (x1,y1, + x2,y2)/2 = midpoints
=(-1,3 + x2,y2) = 2(3,9)
=(-1,3 + x2,y2) = (6,18)
x2=(6-(-1))=7
y2=(18-3)=15

so reflection on (7,15)


T H I S R E A L L Y W O R K S :)


Got it ? o_O
Got it!! thanks
 
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How to integrate 81(2x+3)^-2
Please show complete working not able to understand how to integrate a function
 
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10.PNG
and also how are A and B equal to 2 in this question?
my answer for partial fraction is A=B= 1/1800
 
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part i)
To get f(x), Integrate dy/dx :)

partii)
if d2y/dx^2 > 0 it is minimum value, here put x = 2 in ur d2y/dx^2 you get Value > 0 then it is minimum point :)

omaaaar

Let Dy/Dx =Fx

First Derivate the x+ 4/x^2 wali equation to get F'x
and insert F'x = 0 and calculate the value of x (which is 2)

than double derivate and insert x=2 in it and you will have a value ( 3/2) with is greater than 0
greater than 0 is minimum nature
than add x=2 in the first wali eq ( x + 4/x^2 ) and you will get the minimum gradient.
 
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