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Q.6?
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Mathematics: Post your doubts here!
- Thread starter XPFMember
- Start date
Yes pls. And part b aswell, some confusion i;ve got there
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will take tym... that ok with u?
Ow, I need the answer today, exam tom
Nevermind, take your time but do pass the answer. Thanks in ad
- Messages
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yeah il post it in abt tn to twenty mins insha AllahOw, I need the answer today, exam tom
Nevermind, take your time but do pass the answer. Thanks in ad
- Messages
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ok a parts easyOw, I need the answer today, exam tom
Nevermind, take your time but do pass the answer. Thanks in ad
u know the formula of midpoint( x1+x2)/2 apply this and u will get 1, 4, -2
like 7 plus -5 is 2 and 2/2 =1
aur part two like ii ?
Ow okay. Got it
- Messages
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u need part ii?Ow okay. Got it
- Messages
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or u need the explanation of making up the eq of plane?
I need it. If you can, please go ahead.
Jazakallah
- Messages
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wen two lines are perpendicularthe b1 or directional vector becomes the normal to the ohter vector so here we have n1= 12, 6, -6)
which we took out by (7, 7, -5) -( (-5,1,1) = 12, 6,-6
then we apply formula
r.n=a.n
where r= x y and z
and a is any point on plane
wch can also be A as it passes thru A (1,4,-2)
then we have (x,y,z) . (12, 6 ,-6)= (1, 4,-2). (12, 6. -6)
you will get 12x+6y-6z=48
Remember me in ur prayers please
which we took out by (7, 7, -5) -( (-5,1,1) = 12, 6,-6
then we apply formula
r.n=a.n
where r= x y and z
and a is any point on plane
wch can also be A as it passes thru A (1,4,-2)
then we have (x,y,z) . (12, 6 ,-6)= (1, 4,-2). (12, 6. -6)
you will get 12x+6y-6z=48
Remember me in ur prayers please
Yes definitely. Please remember me too. Got a school test tomorrow, and I am SOO blankwen two lines are perpendicularthe b1 or directional vector becomes the normal to the ohter vector so here we have n1= 12, 6, -6)
which we took out by (7, 7, -5) -( (-5,1,1) = 12, 6,-6
then we apply formula
r.n=a.n
where r= x y and z
and a is any point on plane
wch can also be A as it passes thru A (1,4,-2)
then we have (x,y,z) . (12, 6 ,-6)= (1, 4,-2). (12, 6. -6)
you will get 12x+6y-6z=48
Remember me in ur prayers please
Thanks for the detailed explanation. Thanks!
Yes definitely. Please remember me too. Got a school test tomorrow, and I am SOO blankwen two lines are perpendicularthe b1 or directional vector becomes the normal to the ohter vector so here we have n1= 12, 6, -6)
which we took out by (7, 7, -5) -( (-5,1,1) = 12, 6,-6
then we apply formula
r.n=a.n
where r= x y and z
and a is any point on plane
wch can also be A as it passes thru A (1,4,-2)
then we have (x,y,z) . (12, 6 ,-6)= (1, 4,-2). (12, 6. -6)
you will get 12x+6y-6z=48
Remember me in ur prayers please
Thanks for the detailed explanation. Thanks!
- Messages
- 4,493
- Reaction score
- 15,418
- Points
- 523
yeah s=r theta i dunno abt the latter
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how was the stats paper 62 guys was it difficult or easy wht do i think about the grade threshold/......
- Messages
- 4,493
- Reaction score
- 15,418
- Points
- 523
Yes definitely. Please remember me too. Got a school test tomorrow, and I am SOO blank
Thanks for the detailed explanation. Thanks!
i sure will