Mathematics: Post your doubts here!

[Tkp]

oct nov 11 p-11
6b

 

[PANDA-]

oct nov 11 p-11
6b

I did this one, but I can't find the paper in which I did it on... Anyway!

Sum to infinity is S∞..
S∞ = a1/(1-r)
Both S∞ of both sequences are equal.
a1/1-r = a1/1-r
1/1-r = 4/1-0.25r

P.S. I replaced 1/4(r) with 0.25r cuz it's easier to read and make out from the rest... anyway
Cross multiply

1-0.25r = 4-4r
1-4 = -4r +0.25r
-3 = -3.75r
r= 5/4

Now just replace r= 5/4 in any one of the above S∞

S∞= 1/1-5/4
S∞ = 5

 

[GorgeousEyes]

Please jun012 no.3 v.13 .. jun012 no.7 v.12 .. jun012 v.11 9)iii . Pure Math As . thanks

 

[GorgeousEyes]

Guys is it sufficient to do past papers and variants from year 2009 to 2012 to get an A ? I am talking about Math As .

 

[Soldier313]

Guys, could someone please help out with question No. 10 (b) for the following paper?
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_qp_32.pdf
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w11_ms_32.pdf
Thanks in advance!

hence the final answer is 2.3 radians....
hope it helps!

 

[syed1995]

Guys is it sufficient to do past papers and variants from year 2009 to 2012 to get an A ? I am talking about Math As .

Nothing is ever enough. You can't guarantee that doing all the papers will get you an A. The main thing in maths is concepts.. If your concepts are clear, you'd get an A.. I'd say if you grasp all the concepts from the past papers and variants .. and you think you can score around 60 or so in P1 then sure..

And most importantly always remember Allah.. and offer prayers.. And surely he will reward you

 

[Dudu]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_13.pdf

Help please.

Q10)
iii) (did ii)
iv)
v)

 

[GorgeousEyes]

Nothing is ever enough. You can't guarantee that doing all the papers will get you an A. The main thing in maths is concepts.. If your concepts are clear, you'd get an A.. I'd say if you grasp all the concepts from the past papers and variants .. and you think you can score around 60 or so in P1 then sure..

And most importantly always remember Allah.. and offer prayers.. And surely he will reward you

You are right , thank youu i will incha'allah .

 

[Esme]

When an equation of a plane and equation of a line is given, how do we determine whether the line intersects the plane or not? I know how to find the point of intersection, but if we're asked to tell whether they intersect or not?

 

[GorgeousEyes]

Please jun012 no.3 v.13 .. jun012 no.7 v.12 .. jun012 v.11 9)iii . Pure Math As . thanks

 

[PhyZac]

When an equation of a plane and equation of a line is given, how do we determine whether the line intersects the plane or not? I know how to find the point of intersection, but if we're asked to tell whether they intersect or not?

When there is a line and plane there are two possibilities,

either, intersection or parallel

If parallel, then the normal and line have 0 scalar product! If not then intersecting!

 

[syed1995]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_13.pdf

Help please.

Q10)
iii) (did ii)
iv)
v)

iii .. from ii you get... 2(x-2)^2 + 6

meaning minimum point is at (2,6)

so x is 2 when y is minimum..

f(2)= 2(2^2) -8(2) + 14
f(x)≥6 (Since it's the minimum value)


iv.. the smallest value of A for which G has an inverse.. would be the x-cordinate of the minimum point.. A= 2

v)

g^-1(x)= 2(x-2)^2 + 6
y= 2(x-2)^2 + 6
y-6 = 2(x-2)^2
(y-6)/2 = (x-2)^2
√[(y-6)/2] = (x-2)
2+ √[(y-6)/2] = x

g^-1(x) = 2+ √[(x-6)/2]

 

[PANDA-]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_13.pdf

Help please.

Q10)
iii) (did ii)
iv)
v)

iii) Since you did ii, the vertex of the graph is (-b, c) as in the equation a(x+b)+k... and since a>0, then the graph is opening upwards, so y is >= (greater or equal) c.
iv) I'm gonna guess that this is the x value of the vertex, because at the vertex, a horizontal line would intersect it only at one point. The inverse of f is a function only when it is a one to one function.
v) Meh dunno really.

 

[Dudu]

iii .. from ii you get... 2(x-2)^2 + 6

meaning minimum point is at (2,6)

so x is 2 when y is minimum..

f(2)= 2(2^2) -8(2) + 14
f(x)≥6 (Since it's the minimum value)


iv.. the smallest value of A for which G has an inverse.. would be the x-cordinate of the minimum point.. A= 2

v)

g^-1(x)= 2(x-2)^2 + 6
y= 2(x-2)^2 + 6
y-6 = 2(x-2)^2
(y-6)/2 = (x-2)^2
√[(y-6)/2] = (x-2)
2+ √[(y-6)/2] = x

g^-1(x) = 2+ √[(x-6)/2]

Brilliant. Much Appreciated Mate

 

[Esme]

Are the graphs of sin inverse, cos inverse and tan inverse a part of the syllabus for Paper 3? Should we know how to make these graphs?

 

[PhyZac]

Are the graphs of sin inverse, cos inverse and tan inverse a part of the syllabus for Paper 3? Should we know how to make these graphs?

Yes.

 

[gary221]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s07_qp_3.pdf
q 7 the whole.
plz..

 

[PhyZac]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_3.pdf
q 7 the whole.
plz..

check this
https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-269#post-430384

 

[Esme]

Yes.

Ok thanks. Do you have any notes or anything that'll help me learn to make those graphs?

 

[PhyZac]

Ok thanks. Do you have any notes or anything that'll help me learn to make those graphs?

http://www.examsolutions.net/maths-...gonometry/sec-cosec-cot/graphs/tutorial-1.php