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this is so very easy.. al you have to kp in mind that the gradient of tangent is also gradient og curve at aprticular point they meet. curve =9/2x+3Aslamoalikum
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_12.pdf
Q9 (ii) adn Q 11 (i) and (iii)
differentiate you will get -9/ (2x+3)^2
since its tangent at A x=3
-9 /( 81)
grad = -1/9
now u make an equation with coords 3,1 and grad = -1/9
then u get eq of line 9y= -x+12
notice that C lies on this line... hence to take out coords of C put x=0 as it lies on the y axis
u will get points (0, 4/3)
now take distance of C (0, 4/3) and O ( 0, 0)
and distance C(0, 4/3) and B (0, 3)
the lesser the distance the closer the points are...
the formula of distance is root of (((x1-x2)^2 +(y1- y2)^2))