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Mathematics: Post your doubts here!

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hey guys plz help me in this question.
 

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I replied in the conversation but assuming you didn't get it, i'm doing it here again :)
http://www.mediafire.com/?sd06xlzb4x2tcft <= This was the plan diagram i made.
Now for the solution!​
The area of OCD = 1/2 * r^2 * theta​
The area of OAB = 1/2 * (r + 2)^2 * theta​
So,​
area of ABDC = 1/2 * (4r + 4) * theta​
Now if you equate area of ABDC to 1/3 area of OCD​
you'll get​
r^2 - 12r - 12 = 0​
and the answer the calculator gives after solving is 12.93​
:)

I didn't see it , Thank you a lot . really appreciate your help :)
 
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parthrocks

16/[(2+x)^2]



16*[ (2+x)^ -2]

16*[2^ -2 (1+1/2x)^-2]

4*[(1+1/2x)^-2]

now abbpy binomial theoram on the curly brackets

4*[1 +nx + n(n-1)x^2/2!.............]

4*[1 + (-2)(1/2x) + {(-2)(-2-1)(1/2x)^2}/2!].


4*[1 - x + 3/4 x^2]


4 - 4x + 3x^2 Ans



hope it is clear???
 
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parthrocks

m/j 2011 qstn 2

lg2(x+5) = 5 - lg2(x)

lg2(x+5) + lg2(x) = 5

taking lg2 as comman.

lg2{(x+5)*x} = 5

now as L.H.S is with lg base 2 so we have to convert the other side with base 2 as well.

look here....... lg22^5 = 5*lg22 = 5 (as lg22 is always 1 )

means lg22^5 = 5*lg22 = 5 = lg232

put this in the eq.



lg2{(x+5)*x} = lg232

now remove logarithim from both sides u will get
x^2 + 5x = 32 shown Ans
 
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