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That was a tricky question. well you have to use the frequency density formula that is (freq/column width)=freq density The freq density is the height but here as it is mentioned in the question that for interval 60<t<80 it is 2.8 using the formula you get 0.7 so divide 2.8 by 0.7 you will get 4. so they have multiplied each answer by 4. thus find freq density for each column you will get 0.25, 0.725, 1.066667 now multiply each result by 4 you will get 1, 2.9, 4.26 done!
from the data given in the question we will find the constant (ie: 60 < t < 80 is 2.8cm and F.d of it is 14/20=0.7 so 2.8/0.7= X4
but is it nessecary that we have to multiply by 4??
It's easy!!
Okay it's simple.. First off its written in the as before it that the scale factor is -4 now forget about the negative sign because it just means on the opposite side.. So the ratio between the sides is 1:4 now from similarities the ratio for area is squaring the ratio for the sides so (1:4)^2
Yeah but this method takes a lot longer.. In the exam time factor is really important.
Can you please answer my question above :/?Okay it's simple.. First off its written in the as before it that the scale factor is -4 now forget about the negative sign because it just means on the opposite side.. So the ratio between the sides is 1:4 now from similarities the ratio for area is squaring the ratio for the sides so (1:4)^2
Will be 1:16
Hope that helps
Okay it's simple.. First off its written in the as before it that the scale factor is -4 now forget about the negative sign because it just means on the opposite side.. So the ratio between the sides is 1:4 now from similarities the ratio for area is squaring the ratio for the sides so (1:4)^2
Will be 1:16
Hope that helps
Sure thing muffin!THANK YOU SOOOOOOOOOOoOOoOoOoO much!
Okay Hun hold on.
U know I came to this thread just to post this as it has been bothering me since yesterday and I don't really know how they reached five.. I am so sorry I couldn't help U.. Can some1 please explain it?
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