- Messages
- 169
- Reaction score
- 117
- Points
- 38
although i solved many questions of this type i dont know why my answers are not correct for this question. 
-
We need your support!
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Mathematics: Post your doubts here!
- Thread starter XPFMember
- Start date
although i solved many questions of this type i dont know why my answers are not correct for this question.
- Messages
- 169
- Reaction score
- 117
- Points
- 38
i hate these questions. any idea for frequecy density calculation >(a)
Range = The Highest boundary of the Highest Class (in this case 5) - The Lowest boundary of lowest class (in this case 1) = 5-1 = 4
(b)
Median of a data with an 'odd' total frequency = [(total frequency+1)/2]th number = (125+1) = 63rd number = 2
(c)
mode is the number with highest freq. so it is, of course, 1.
- Messages
- 2
- Reaction score
- 2
- Points
- 13
i would like someone to show me how to solve math paper 4 variant 1 oct/nov 2010 last question of the paper
- Messages
- 1,665
- Reaction score
- 2,400
- Points
- 273
can sum one tell me how to make matrices of transformations ......plz quickly
- Messages
- 2
- Reaction score
- 2
- Points
- 13
either memorize them or just use the method of I,J(10
01)
link plz?
- Messages
- 169
- Reaction score
- 117
- Points
- 38
coz there r 2 pencils and out of these 2, either 1st will be green, or the 2nd one will be green.
there are two chances
1:
1st one is green
P(1st green) = (4/9) * (5/8) = 20/72
2:
2nd one is green
P(2nd green) = (5/9) * (4/8) = 20/72
so having the two mutually exclusive events (events which can NOT occur at the same time) we add the 2 probabilities.
P(only 1 is green) = (20/72) + (20/72) = 2(20/72)
got it?
if no, then try making a tree diagram, that'll make u understand it way better In Shaa Allah
and if u dont understand it then, then i cant do anything else
(c) The possibilities are
Green and then Red (i will denote this as GR)
Thus
GR, GB, BG, RG
so it will be
P(GR) + P(GB) +...
will u remind me tomorrow? actually i have an exam tomorrow and to explain that, it needs a lot of time. so, u know. I have to study :/
- Messages
- 1,095
- Reaction score
- 899
- Points
- 123
best way is to memorise them , bt f provided wth image coordinates as well as object coordinates so find by them
- Messages
- 67
- Reaction score
- 80
- Points
- 8
it's BCA = 38, not BCDhow is BCD 93?
BCD = BCA + ACD
- Messages
- 1,665
- Reaction score
- 2,400
- Points
- 273
okay.....setting it up as my reminder to remind the weird guy with exams to answer my questions......
- Messages
- 169
- Reaction score
- 117
- Points
- 38
yes i got it. thank youcoz there r 2 pencils and out of these 2, either 1st will be green, or the 2nd one will be green.
there are two chances
1:
1st one is green
P(1st green) = (4/9) * (5/8) = 20/72
2:
2nd one is green
P(2nd green) = (5/9) * (4/8) = 20/72
so having the two mutually exclusive events (events which can NOT occur at the same time) we add the 2 probabilities.
P(only 1 is green) = (20/72) + (20/72) = 2(20/72)
got it?
if no, then try making a tree diagram, that'll make u understand it way better In Shaa Allah
and if u dont understand it then, then i cant do anything else
- Messages
- 169
- Reaction score
- 117
- Points
- 38
second part ? is it right the way i am taking the bearing ?No. Extend your line (the dark blue one) so that it touches BC
180 + ACD + ACB = bearing of B from C
as we know BAC = ACD
so 180 + ACD + ACB = 180 + BAC + ACB
150 + ACB + BAC = 180
ACB + BAC = 30 = ACD + ACB
180 + ACD + ACB = 180 + 30 = 210
Last edited: