• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Pernee26 said:
Question 8 a) ii) please solve it. :)
http://www.xtremepapers.me/CIE/Cambridge IGCSE/0580 - Mathematics/0580_w05_qp_4.pdf
Click to expand...


SEE

The cost of each book is increased by $2 so the total number of books bought now can be 40/x+2

The books that can be bought now are one less then the (part i) so they are 40/x - 1

As both of them show number of books you can equal them 40/x - 1 = 40/x+2 and then solve...


MATH ANGEL

You don't mind us answering? Right? :)
 
XPFMember

XPFMember

XPRS Moderator
Messages
4,555
Reaction score
13,290
Points
523
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

let me make it clear...
the no. of books at the new rate is 40/(x+2)

and no. of books at the old rate was 40/x

at new price we'll get one book less than b4...so we can make an eqn.

(40/x) - 1 = 40/(x+2)

...and solve


captain u did it correct but since u didnt put any brackets ...i've done it again :)
 
CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

:) I could not think of what to do with that HERE... I mean I did thought of it that the person who go through it may put -1 with the denominator...
 
CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Abid357 said:
Qns. 20 (b)... I managed to get one mark out of two :/

And another question... how do you 'DRAW' planes of symmetry? Like do you just draw a (dotted) line or a 3D mirror inside the shape?

Jazak Allah.
Click to expand...

Walikum Salaam! :)

If you look at the shape of graph between 8 to 10 seconds its a trapezium with height 2 units (10 - 8 = 2)

The distance traveled between 8 and 10 seconds is 100 - 80.6=19.4 m

The distance traveled during 8 to 10 seconds is given by the trapezium area formula too...

So

½ ( 12.4 + v ) × 2 = 19.4

Solve for v...

Answer 7 m/s

For the other question I guess just the dotted line....
 
A

Abid357

Messages
34
Reaction score
4
Points
18
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Yay ! Jazak Allahu khairan ^^
 
XPFMember

XPFMember

XPRS Moderator
Messages
4,555
Reaction score
13,290
Points
523
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

hasman123 said:
http://www.xtremepapers.me/CIE/Cambridg ... _qp_22.pdf
Q 18) part c....... I dont get it. also what it is an iddentity matrix?
Click to expand...

Assalamoalaikum!!

well identity matrix is a matrix which has elements in the diagonal top left to bottom right as 1 and others zero...
here they said it's a 2x2 matrix so it'll be

{1 0}
{0 1}

now i think u can do the further calculations easily as per the eqn given...if u need more assistance with that...i'll surely try to help u InshaAllah :)
 
XPFMember

XPFMember

XPRS Moderator
Messages
4,555
Reaction score
13,290
Points
523
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

CaptainDanger said:
Pernee26 said:
Question 8 a) ii) please solve it. :)
http://www.xtremepapers.me/CIE/Cambridge IGCSE/0580 - Mathematics/0580_w05_qp_4.pdf
Click to expand...


SEE

The cost of each book is increased by $2 so the total number of books bought now can be 40/x+2

The books that can be bought now are one less then the (part i) so they are 40/x - 1

As both of them show number of books you can equal them 40/x - 1 = 40/x+2 and then solve...


MATH ANGEL

You don't mind us answering? Right? :)
Click to expand...

Assalamoalaikum!!

i think u editted ur post ...right?? :twisted: :D
anyways i just saw the later part of it now...didnt notice it before...

i dont mind u ppl answering at all... :) thnx for answering :good:
that.... kind of makes my work easier....i mean i dont have to work out the complete solutions here :D and then its a practice for u :D

may Allah bless u all
 
CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

I didn't edit it... If I had then under the post it would be written... :) You noticed now...

GOOD :D
 
XPFMember

XPFMember

XPRS Moderator
Messages
4,555
Reaction score
13,290
Points
523
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

nopes u must have editted b4 i posted my reply :D
anyways. :)
 
P

pprgeek

Messages
5
Reaction score
0
Points
11
CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

pprgeek said:
Hey guys and Salaam to all !

I'm back with some of my doubts to this extremely useful thread. They are as follows:-

Q10
Q16
Q21b
(Variant 1)
Paper 2: http://www.xtremepapers.me/CIE/Cambridge IGCSE/0581 - Mathematics Extended/0581_s09_qp_2.pdf

Q9
Paper 2: http://www.xtremepapers.me/CIE/Cambridge IGCSE/0581 - Mathematics Extended/0581_w09_qp_21.pdf

Once again everyone and Math angel thakx in advance !! :wink:

Have a gud day !
Click to expand...

WALIKUM SALAAM!

FIRST PAPER

Q10

LCM is cd

So when you add them it becomes like this
d + c - (c-d)/cd

d + c - c + d /cd

2d/cd

d d cancels out

Answer

2/c


Q21 b

First find BA

Which is



Then compare as the question says AB=BA

So you can see that

2x+12 = 2x+12

3x+6=21

14=2x+4

15=15

You can find x from the BOLD ones...

3x+6=21
3x=15
x=5

From the other answer will always be the same... :)

SECOND PAPER

Check this PAGE

We have already discussed the eliminating method for simultaneous linear equations.... Go through that and then solve yours... If you still could not then we are here for help...
 
P

pprgeek

Messages
5
Reaction score
0
Points
11
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

CaptainDanger said:
pprgeek said:
Hey guys and Salaam to all !

I'm back with some of my doubts to this extremely useful thread. They are as follows:-

Q10
Q16
Q21b
(Variant 1)
Paper 2: http://www.xtremepapers.me/CIE/Cambridge IGCSE/0581 - Mathematics Extended/0581_s09_qp_2.pdf

Q9
Paper 2: http://www.xtremepapers.me/CIE/Cambridge IGCSE/0581 - Mathematics Extended/0581_w09_qp_21.pdf

Once again everyone and Math angel thakx in advance !! :wink:

Have a gud day !
Click to expand...

WALIKUM SALAAM!

FIRST PAPER

Q10

LCM is cd

So when you add them it becomes like this
d + c - (c-d)/cd

d + c - c + d /cd

2d/cd

d d cancels out

Answer

2/c


Q21 b

First find BA

Which is



Then compare as the question says AB=BA

So you can see that

2x+12 = 2x+12

3x+6=21

14=2x+4

15=15

You can find x from the BOLD ones...

3x+6=21
3x=15
x=5

From the other answer will always be the same... :)

SECOND PAPER

Check this PAGE

We have already discussed the eliminating method for simultaneous linear equations.... Go through that and then solve yours... If you still could not then we are here for help...
Click to expand...


Thanx dude !
You just cleared all my doubts !! :Yahoo!:

And sorry i made a mistake.

It was Q12 not Q9 in this paper:-

Paper 2: http://www.xtremepapers.me/CIE/Cambridge IGCSE/0581 - Mathematics Extended/0581_w09_qp_21.pdf

Hope you could help :)
 
CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Yeah sure I can... :)


Q12
You have use the formula for (3x-2)² which is (a - b)² = a² -2ab + b²

16-4 (3x-2)²

16-4 (9x²-12x+4)
16-36x²+48x-16
-36x²+48x is the Answer

LOCUS PART
 
CaptainDanger

CaptainDanger

Messages
5,877
Reaction score
4,244
Points
323
Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

student92 said:
on07 p2 q16 how do we solve this? thanks
Click to expand...

Q16
(a)

To find the length of tank of the real car you have to take the cube root of 64... Which is 4...

Similarly for the model car you have to take the cube root of .125 which is .5...

Now the length of the real car is 8 times the length of model car...

.5 into 8 = 4 (PROVED)

(b)

Take square root of .0175... It will give you the length of model.... As we know that the length of real one will be 8 times the length of model car so multiply it by 8 to get the length of real car... Then to find the area of the real one's Window take square of the this value... Length into Length... It will give you the answer...
 
You must log in or register to reply here.
Top