M2 (paper 5)

[yasser37]

Hi

I was solving past papers and These are the doubts I have so far
please help

November 09 , 51, Q4 (ii)
November 10 . 53 , Q4(ii)
November 09 , 52 ,Q1
June 10 , 53, Q(i) ---- A Drawing of angles taken would be greatly appreciated
June 09, 5, Q2 (i) Same as above and Q(6) (ii)

I hope that someone can help me before my exam
+rep for helper

 

[ParanoidAleveler]

For November 09 , 51, Q4 (ii)

So you found the force to be 2 N in the first part right?
now you use F = ma.
so 2cos(theta) = 0.12 x (v^2/ r) (cuz a = v^2/r)

therefore, 2 x (0.4/0.5) = 0.12 x (v^2/ 0.4)

v = 2.31 ms^-1



the radius is 0.4 because a triangle is formed with 0.5 as the hypotenuse.

 

[ParanoidAleveler]

November 10 . 53 , Q4(ii)

Friction force acts in direction of of the force at B BUT it is parallel to the plane (because friction is between the rod and the plane)

so, resolve parallel to the plane.

Fcos30 + Friction = 15cos60

 

[abuhantash]

June 09 Q2
First find AG by the hyp theorem AG=10.68
then take moments about A 12 x 10.68 = T x 20
and get T

For question 6 (ii)
you need to find two EPE
EPE1 = 0.5 x (4/0.25) x (0.75)^2 EPE2 = 0.5 x (8/0.25) x (o.75)^2
EPE1 = 4.5 EPE2 = 9
Add them and you should get 13.5J

 

[abuhantash]

I have URGENT questions please.
JUne 10 P53 Q4 (i) I dont get how they form the moments formula
June 10 p53 Q 5 (ii) ZDVVIf someone could explain what I must do when they ask for "min and mazx" speeds in the circular motion!

 

[MagicmanFarhanul]

can any of u guys solve the elasticity sum of ,mj 10(1) q6 ,plz i really dont get why are the taking the change in lenght ,i mean the value of x in the formula.T=Lemda X/l ,as 1

 

[abuhantash]

can any of u guys solve the elasticity sum of ,mj 10(1) q6 ,plz i really dont get why are the taking the change in lenght ,i mean the value of x in the formula.T=Lemda X/l ,as 1

yes please someone answer this URGENTLY =[

 

[MagicmanFarhanul]

can any of u guys solve the elasticity sum of ,mj 10(1) q6 ,plz i really dont get why are the taking the change in lenght ,i mean the value of x in the formula.T=Lemda X/l ,as 1

yes please someone answer this URGENTLY =[

i found out no logic in it