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M1 ON 13 MAY ,WHO HAS THE BEST PREPATION,Post your doubts here?

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Guyz help me with the M1,Specially with the General motion in a straight line and forces?
 
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For the first part
The question tells you that there is a force of 12 N acting on the block and becuase it's a frictional force,it acts towards the right.
So this is the only force acting on the object and you know that F=ma and since a is 0.15 the acceleration -0.8
From this you know that U=3 t=2 and a =-0.8
then you can calculate V which gives you a vaalue of 1.4
So now you know that the block loses 7.2 Joules of energy so find the Kinetic energy loss at Y subtract this from 0.072 and find the value of V when it leaves.
I think you shold be able to go on from here>
Hope you understand
Good luck
 
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For the first part
The question tells you that there is a force of 12 N acting on the block and becuase it's a frictional force,it acts towards the right.
So this is the only force acting on the object and you know that F=ma and since a is 0.15 the acceleration -0.8
From this you know that U=3 t=2 and a =-0.8
then you can calculate V which gives you a vaalue of 1.4
So now you know that the block loses 7.2 Joules of energy so find the Kinetic energy loss at Y subtract this from 0.072 and find the value of V when it leaves.
I think you shold be able to go on from here>
Hope you understand
Good luck
I have done this too
but what about the graph....
Please help
 
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For part one my graph looked something like this with V on the y axis and T on the x axis

I think ur graph is wrong, because after collision the motion is towards a direction opposite to the initial motion. therefore, the velocity becomes negative, i think the graph shud be this:
 

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can someone pleas tell me what is the work energy equation
and how does it link p.e, k.e, work done against resistance and work done by driving force
 
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can someone pleas tell me what is the work energy equation
and how does it link p.e, k.e, work done against resistance and work done by driving force
POTENTIAL ENERGY =mgh
Kinetic Energy=1/2 mv^2
Total Energy=Potential Energy+Kinetic Energy
Loss in Potential =Gain in Kinetic or viceversa
Work done by driving force=F S
Workdone by Resistance force=R S (R IS THE Resistance force can be calculated form F-R=ma)
other Equations can be made according to the situation given?
 
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Someone please explain to me Question no. 2 from May-June 2012-Paper 42. I have a serious problem in my concept and need a thorough explanation. And also question 4 and 5! Please guys.

If possible upload a podcast here (like explain it in and record your voice and send here)!!!

Please guys. In total chaotic situation right now :(
 
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