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How was 9709 paper 4 (Mechanics 1)?

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I just solved it and I'm getting 1.9524m for my length of string.

T=1.0666...
a=2/3 (for 0.7m), then 2.8 (after the string breaks)

v (when string breaks) = *root* (2 x 2/3 x 0.7) = 0.96609
then it increases to 2
So
2^2 = 0.96609^2 + 2(2.8)s
s = 0.5476

So the length of string will be 2.5-0.5476 = 1.9523
hey can u show me how u solved for tension and acceleration in the first place?
 
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same as yours !!!! dont worry our answers are 100% correct !!!

Haha I'm not wrong

Mass of A (on the ramp) was 0.5kg, mass of B was 0.1 kg
The ramp was 2.5m long and 0.7m high, so that means that sin(Theta)=7/25

Component of A down the ramp will be mgsin(theta), and hence you get 1.4N

Use newtons second law, F=ma

1.4 - T = 0.5a
T - 1 = 0.1a

Add to get rid of T,

0.4 = 0.6a, hence a = 2/3 and T = 1.06666....
 
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Haha I'm not wrong

Mass of A (on the ramp) was 0.5kg, mass of B was 0.1 kg
The ramp was 2.5m long and 0.7m high, so that means that sin(Theta)=7/25

Component of A down the ramp will be mgsin(theta), and hence you get 1.4N

Use newtons second law, F=ma

1.4 - T = 0.5a
T - 1 = 0.1a

Add to get rid of T,

0.4 = 0.6a, hence a = 2/3 and T = 1.06666....
yes .. thatss right
 
Messages
170
Reaction score
229
Points
53
Haha I'm not wrong

Mass of A (on the ramp) was 0.5kg, mass of B was 0.1 kg
The ramp was 2.5m long and 0.7m high, so that means that sin(Theta)=7/25

Component of A down the ramp will be mgsin(theta), and hence you get 1.4N

Use newtons second law, F=ma

1.4 - T = 0.5a
T - 1 = 0.1a

Add to get rid of T,

0.4 = 0.6a, hence a = 2/3 and T = 1.06666....
OMG. :( This question is a disaster for me. :( :( :( :(
I don't know.. I'm losing that 8 marks for sure then. :'(
 
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Is there error carried forward in question 2 of the freefall because in i) I wrote all the steps correct but i suppose i put the values incorrect on the calculator so ii) also will be wrong .i'm hoping that i'll lose 1 mark in this question only.Is it possible?
 
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Is there error carried forward in question 2 because in i) I wrote all the steps correct but i suppose i put the values incorrect on the calculator so ii) also will be wrong .i'm hoping that i'll lose 1 mark in this question only.Is it possible?
main marks are for main logic applied to the question !!! yes it is possible
 
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