• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

HELP HELP!

Messages
585
Reaction score
237
Points
53
Just one tiny wincy question..WHY IS THE ANSWER A TO JANUARY 2010 QUESTION 5 ?? I THOUGHT IT WAS C :,( please help
 
Messages
40
Reaction score
14
Points
18
chemistry :'(
Dun Cwy :(
The question says increasing boiling temperature and there are 3 gases!
You know the alkanes are saturated hydrocarbons and the boiling temperature increases as the chain increases.
Here CH4 is the Methane and it has the lowest boiling temperature of -164 oC
HCL, Hydrogen Chloride gas has the boiling temperature of -85 oC
HF, Hidrogen Flouride gas has the boiling temperature of 19.5 oC

Therefore, the answer is A CH4, HCL, HF

Does this help? ;)
Or anyone else here to elaborate more? :(
 
Messages
585
Reaction score
237
Points
53
Dun Cwy :(
The question says increasing boiling temperature and there are 3 gases!
You know the alkanes are saturated hydrocarbons and the boiling temperature increases as the chain increases.
Here CH4 is the Methane and it has the lowest boiling temperature of -164 oC
HCL, Hydrogen Chloride gas has the boiling temperature of -85 oC
HF, Hidrogen Flouride gas has the boiling temperature of 19.5 oC

Does this help? ;)
Or anyone else here to elaborate more? :(
ohhhhh .............. wow, think the stress caught up with my thinking..
 
Messages
40
Reaction score
14
Points
18
Aww Yew Need Answer To This? :p
It is about ionic equation.

Sr2+(aq) + SO42− (aq) → SrSO4(s)

You have to write the state symbols as well if you want to get 2 marks;D
In perfect ionic equations, we don't have to show Na+ ions and Cl- ions as they are spectator ions and left out in the equation.

You want more help on this?:(
 
Messages
585
Reaction score
237
Points
53
nah
Aww Yew Need Answer To This? :p
It is about ionic equation.

Sr2+(aq) + SO42− (aq) → SrSO4(s)

You have to write the state symbols as well if you want to get 2 marks;D
In perfect ionic equations, we don't have to show Na+ ions and Cl- ions as they are spectator ions and left out in the equation.

You want more help on this?:(
nah, i figured it out a while ago... but thanks anyway :)
 
Messages
585
Reaction score
237
Points
53
i
Hey:( I even didnt know this:( The asnwer is D. But for me A is the right one :(
Im going through the notes to solve ito_O
i thought it was C :(? y'know? electrons leave the 3rd orbital first then 2nd then the first..3p 3s 2p 2s 1s
 
Messages
40
Reaction score
14
Points
18
i
i thought it was C :(? y'know? electrons leave the 3rd orbital first then 2nd then the first..3p 3s 2p 2s 1s
Hey.. you mean this question rite?

8. A sample of gas was prepared for use in helium-neon lasers. It contained 4 g of helium
and 4 g of neon. What is the ratio of helium atoms to neon atoms in the sample?
A 1 : 1
B 2.5 : 1
C 1 : 5
D 5 : 1
 
Messages
585
Reaction score
237
Points
53
Hey.. you mean this question rite?

8. A sample of gas was prepared for use in helium-neon lasers. It contained 4 g of helium
and 4 g of neon. What is the ratio of helium atoms to neon atoms in the sample?
A 1 : 1
B 2.5 : 1
C 1 : 5
D 5 : 1
nahh.. i get that..do you? :)
 
Messages
585
Reaction score
237
Points
53
Haha.. Naw :/ I didnt:( Can you tell me :)

This question is the one you asked :/
Moles = mass/ molar mass

sample------------------ Helium --------- Neon
Mass of sample----------4g --------------4g
Molar mass--------------4g/mol --------20.2g/mol
Mole ---------------------4/4------------ 4/20.2
----------------------------1 ----------------0.2

Divide by smallest-------- 1/0.2--------- 0.2/0.2

Ratio-------------------------------- 5 : 1

The answer is D
 
Messages
40
Reaction score
14
Points
18
Moles = mass/ molar mass

sample------------------ Helium --------- Neon
Mass of sample----------4g --------------4g
Molar mass--------------4g/mol --------20.2g/mol
Mole ---------------------4/4------------ 4/20.2
----------------------------1 ----------------0.2

Divide by smallest-------- 1/0.2--------- 0.2/0.2

Ratio-------------------------------- 5 : 1

The answer is D

Aww ;D Thank Youh! Urgh.. I Did A Mistake :/
I was correct upto this level

Mole ---------------------4/4------------ 4/20.2
----------------------------1 ----------------0.2

But i forgot to divide by smallest. >.<
Hehe:p

Btw, it is the question you asked >> June 2010 Unit 1 question 8.
What is that electron question. I May Help ;D
 
Top