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Further Mathematics: Post your doubts here!
- Thread starter abcde
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Both of them will be counted as two subjects
thxs very much for your help....If u don't mind, could you help me with another circular motion Qs from nov 2007 Q4 Paper 2? thxs
Hi Everyone, could you please help me with this question on Geometric Distribution?
This is a past year question from CIE further maths paper 2 , November 2002 Q10...Thxs very much....really appreciate it
An author sends his first manuscript to a large number of publishers C, D, E,...in turn only appproaching each one after the first, if the one before has refused it. There is a constant probability 1/4 that his manuscript will be accepted by each publisher approached. The random variable M is the number of publishers approached, up to and including the one who accepts the manuscript.
Write down the value of E(M) and Var (M)....I got this part...The answers are E(M) = 4 and Var (M) = 12...
This is the part I got stuck with.....
For his second manuscript the author decides to approach two other publishers A then B for each of whom probability o f acceptance is 1/2. before he approaches C, D , E, .....The probability of acceptance by each publisher remains 1/4. The random variable N is the number of A, B, C, D , E....approached up to and including the one who accepts his manuscript. Write down the first few terms of the series for E(M) and E(N). By comparing corresponding terms, after the second and using your value for E(M), show that E(N) = 5/2.
Use a similar method to show that E(N^2) = 27/2
Thxs very much
This is a past year question from CIE further maths paper 2 , November 2002 Q10...Thxs very much....really appreciate it
An author sends his first manuscript to a large number of publishers C, D, E,...in turn only appproaching each one after the first, if the one before has refused it. There is a constant probability 1/4 that his manuscript will be accepted by each publisher approached. The random variable M is the number of publishers approached, up to and including the one who accepts the manuscript.
Write down the value of E(M) and Var (M)....I got this part...The answers are E(M) = 4 and Var (M) = 12...
This is the part I got stuck with.....
For his second manuscript the author decides to approach two other publishers A then B for each of whom probability o f acceptance is 1/2. before he approaches C, D , E, .....The probability of acceptance by each publisher remains 1/4. The random variable N is the number of A, B, C, D , E....approached up to and including the one who accepts his manuscript. Write down the first few terms of the series for E(M) and E(N). By comparing corresponding terms, after the second and using your value for E(M), show that E(N) = 5/2.
Use a similar method to show that E(N^2) = 27/2
Thxs very much
Hi everyone,
I got stuck with this question from CIE further maths past year papers, november 2004 Q11 paper 2
Please help..I cannot draw the diagram here but I will type the Qs...
This is the link to the diagram from extreme papers
http://www.google.com.bn/url?sa=t&r...w4HgBA&usg=AFQjCNHS-H5M_GXizeXYhyFjyFN5FXEg9A
A ring Pof mass m kg is threaded on a smooth semicircle wire with centre C and radius a m, fixed in a horizontal plane. A light elastic string connects P to D, a fixed point on the axis of the semicircle through a small distance from its equilibrium position E and is released from rest at time t = 0. In the subsequent motion, angle PCD = theta and beta is the angle which PD makes with the tangent at P. Given that theta is small enough for theta square and higher powers to be neglected, show that
(i) PD = am
(ii) the tension TN in the string is constant
(iii) Beta = pie/2 - 2theta
I have solved the first 2 parts....The part (iii) and last 2 parts are the ones I got stuck with....
Write down an approximate equation of motion of P on the wire.
The period of the motion of P is approximately 2 s. Find the value of T in terms of m and a and find the solution of the approximate equation of motion for which theta > 0 when t = 0 and 0.5 s after release , d theta/ dt = -0.03 rad per second..
Thxs
I got stuck with this question from CIE further maths past year papers, november 2004 Q11 paper 2
Please help..I cannot draw the diagram here but I will type the Qs...
This is the link to the diagram from extreme papers
http://www.google.com.bn/url?sa=t&r...w4HgBA&usg=AFQjCNHS-H5M_GXizeXYhyFjyFN5FXEg9A
A ring Pof mass m kg is threaded on a smooth semicircle wire with centre C and radius a m, fixed in a horizontal plane. A light elastic string connects P to D, a fixed point on the axis of the semicircle through a small distance from its equilibrium position E and is released from rest at time t = 0. In the subsequent motion, angle PCD = theta and beta is the angle which PD makes with the tangent at P. Given that theta is small enough for theta square and higher powers to be neglected, show that
(i) PD = am
(ii) the tension TN in the string is constant
(iii) Beta = pie/2 - 2theta
I have solved the first 2 parts....The part (iii) and last 2 parts are the ones I got stuck with....
Write down an approximate equation of motion of P on the wire.
The period of the motion of P is approximately 2 s. Find the value of T in terms of m and a and find the solution of the approximate equation of motion for which theta > 0 when t = 0 and 0.5 s after release , d theta/ dt = -0.03 rad per second..
Thxs
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Did anybody take Further Mathematics this session?
Hi Neebom, Thxs so much for your help...really really appreciate it.....I have two left questions left that I havent been able to solve..The ones I have posted on pg 24....Whenever u r free,could you please help me to have a look at it?? I am really sori to bother u ....thxs again
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Hey!
Does anybody have good notes on Rational Functions and Exponentials and Logarithms? i need them for a test =[
Does anybody have good notes on Rational Functions and Exponentials and Logarithms? i need them for a test =[
Hiya...as I am studying on my own for further maths, I find the textbook on Further Pure Mathematics bu Brian Gaulter and MArk Gaulter very useful.....U can check it out...I think in the previous pages, one of our members did post it up some link
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Hi guys, can someone do this one please ' In a traingle OAB, O is the origin, A is the point (0,6), B is (6,0). Find the equation of the three medians of the triangle.'
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yeah, i took it
paper 22. Sahib, Just wanna ask how was paper 22? Not bad right
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I took it as well this session. P1 was very good. P22 had a tricky momentum question, but otherwise simple.
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What were your 2 possible values of e in that tricky momentum question ?
Hi Saad, U posted the solutions of SHM by Raja on pg 23..I can't seem to download it...Is it possible for you to upload the solution on november 2004 Q11, simple harmonic motion, paper 2? so sori to bother u...thxs so much
Hi Everyone,
I know some of you have just finished ur paper 2 and may not want to try anymore Qs...But pls pls help help me with this question on Geometric Distribution when u r free...thxs thxs so much
This is a past year question from CIE further maths paper 2 , November 2002 Q10...Thxs very much....really appreciate it
An author sends his first manuscript to a large number of publishers C, D, E,...in turn only appproaching each one after the first, if the one before has refused it. There is a constant probability 1/4 that his manuscript will be accepted by each publisher approached. The random variable M is the number of publishers approached, up to and including the one who accepts the manuscript.
Write down the value of E(M) and Var (M)....I got this part...The answers are E(M) = 4 and Var (M) = 12...
This is the part I got stuck with.....
For his second manuscript the author decides to approach two other publishers A then B for each of whom probability o f acceptance is 1/2. before he approaches C, D , E, .....The probability of acceptance by each publisher remains 1/4. The random variable N is the number of A, B, C, D , E....approached up to and including the one who accepts his manuscript. Write down the first few terms of the series for E(M) and E(N). By comparing corresponding terms, after the second and using your value for E(M), show that E(N) = 5/2.
Use a similar method to show that E(N^2) = 27/2
Thxs very much
I know some of you have just finished ur paper 2 and may not want to try anymore Qs...But pls pls help help me with this question on Geometric Distribution when u r free...thxs thxs so much
This is a past year question from CIE further maths paper 2 , November 2002 Q10...Thxs very much....really appreciate it
An author sends his first manuscript to a large number of publishers C, D, E,...in turn only appproaching each one after the first, if the one before has refused it. There is a constant probability 1/4 that his manuscript will be accepted by each publisher approached. The random variable M is the number of publishers approached, up to and including the one who accepts the manuscript.
Write down the value of E(M) and Var (M)....I got this part...The answers are E(M) = 4 and Var (M) = 12...
This is the part I got stuck with.....
For his second manuscript the author decides to approach two other publishers A then B for each of whom probability o f acceptance is 1/2. before he approaches C, D , E, .....The probability of acceptance by each publisher remains 1/4. The random variable N is the number of A, B, C, D , E....approached up to and including the one who accepts his manuscript. Write down the first few terms of the series for E(M) and E(N). By comparing corresponding terms, after the second and using your value for E(M), show that E(N) = 5/2.
Use a similar method to show that E(N^2) = 27/2
Thxs very much
Hi, Can you solve part (i) and (ii) of Q9 of this paper http://papers.xtremepapers.com/CIE/...athematics - Further (9231)/9231_w04_qp_1.pdf
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search and like " FURTHER MATHS PRODIGIES" on facebook and go to "Files+Photos" which contains nearly all the solutions to past papers questions of Pure+Mechanics+Stats
well there
is nothing on it. Can you please solve it =D
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There's everthing there.Go to both Files and Photos and search carefully and slowly.
You'll never have to ask anyone anything again. Its the best possible help.
https://www.facebook.com/groups/furthermathsprodigies/files/
https://www.facebook.com/groups/furthermathsprodigies/photos/