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Chemistry: Post your doubts here!

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View attachment 63791
I really can't figure this out. How can the formula be like that? Isn't it going to be 2 Ca ? The answer is C btw. Helppp
It says salt formation so the ratio of acid to calcium would be 2:1 for example for Butanedioic acid seperate into two parts and react it with calicum and it will look like this :
CH2COO- + Ca2+ = (CH2COO)2 Ca
And do that for the rest and so its formula will become
C8H8O8Ca2
Divide by 2 and so the E.F becomes
C4H4O4Ca
 
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pretty stupid question but we are given data booklet in chemistry paper 1 right? we are allowed to use it right
 
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It says salt formation so the ratio of acid to calcium would be 2:1 for example for Butanedioic acid seperate into two parts and react it with calicum and it will look like this :
CH2COO- + Ca2+ = (CH2COO)2 Ca
And do that for the rest and so its formula will become
C8H8O8Ca2
Divide by 2 and so the E.F becomes
C4H4O4Ca
Thank youuuuu
 
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why is it C and not B?
As the reactants react they produce auto catalyst with the products so the rate increases but later after some time the the rate will decrease due to low substrate concentration.
 
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As the reactants react they produce auto catalyst with the products so the rate increases but later after some time the the rate will decrease due to low substrate concentration.
is shape of graph B for conc against time for auto-catalytic reaction?
 
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Guys check the page @threesciencesforalevel on insta...
You'll be surprised at what you will find. Unfortunately, I just got to see it now :"(
 
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Plz someone guide me on how to balance such equations...will be really grateful
 
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can anyone pls explain me how to solve these two questions
 

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The answer to this is C...although I know that there will be no dipole moment in CO2 but does that also mean that it will not have permanent dipole-dipole interactions?

CO2 does not have pd-pd interaction as it has no overall dipole moment
 
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CO2 does not have pd-pd interaction as it has no overall dipole moment
But due to difference in electronegativities, it DOES have dipoles...so won't there b pd-pd forces due to the presence of dipoles, despite the fact that it has no dipole moment ?
 
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