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P decomposes to form R at a 1:1 ratioohh but like the only part i dont get is for the rest i took (2- 2x) but for p why are we supposed to to take 2-x in this condition
P decomposes to form R at a 1:1 ratio
If X moles of R are formed X moles of P decompose
View attachment 62496
came in a latest p2... so can come in p1..
the 2nd equation might also have 3Cl- in products as spectator ions.
Thanks a lot! This was really complex for me idk why : / but i got it!As zellyman said, P is same in both so in first situation:
P = nRT/V
You don't know n but you do know that n = mass/Mr and you have mass so substitute that in, convert T from C to K, convert V from 0.025 to 0.000025 if you want and R is 8.31 as you know, but keep V in dm^3 anyway cause units will cancel out as you'll be able to see if you're good at maths.
P = mass x R x T/V x Mr
P = (0.1 x 8.31 x 373)/(0.025 x Mr), no need to go any further as the final answer isn't a full answer either. It's enough to see that
P = 0.1 x 8.31 x 373/0.025 x Mr
In second situation:
P = nRT/V
You have n (1), rest as usual.
P = 1 x 8.31 x 273/22.4, again, enough to see that P = 8.31 x 273/22.4
Equate both P and Mr subject of formula:
(8.31 x 273)/(22.4) = (0.1 x 8.31 x 373)/(0.025 x Mr)
0.025 x Mr = 0.1 x 8.31 x 373 x 22.4/8.31 x 273
8.31 cancel out
0.025 x Mr = 0.1 x 373 x 22.4/273
Mr = 0.1 x 373 x 22.4/273 x 0.025
D is the answer.
As Mn2+ is produced, it catalyses the reaction according to the question. So as reaction proceeds, faster decrease in reactant (MnO4-) is seen. Enough to reach answer.Why B and not C? what 's the difference?View attachment 62495
Solves this ,A friend gave it to me to tell him why,and I honestly have no idea C is the answerView attachment 62494
Guys i recommend learning the balancing of this equation :
3 Cl2 + 6 NAOH = 5 NACl + NAClO3 + 3 H2O
it can save time.. And comes quite often in calculation Qs.
can one of you help me with this? I can't understand why the answer is B - thanks
Both 1, and 2 will cause hydrolysis of the ester group. Na does not react with any group present.can one of you help me with this? I can't understand why the answer is B - thanks
Thanks! It had an easy logic but I messed up.1 is true cause of the COOCH3 branch, it's an ester, so H2SO4 will hydrolyze it.
2 is true cause again, COOCH3 is an ester, alkaline hydrolysis of esters will occur due to NaOH.
3 not true cause no open OH or OOH with which sodium metal can react.
can one of you help me with this? I can't understand why the answer is B - thanks
Damn. I talked to a friend (absolute genius) and he pointed out that it's perhaps cause CO doesn't get oxidized in the atmosphere. Which would make sense cause normally you see that when CO is produced, it like, remains in the air ya know. It harms us and stuff. Unlike NO which we do in paper 3 which 'readily oxidized to NO2' when in contact with air. I presume the same goes for sulphur. Hence why carbon is rejected.
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