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CH3COOCH2CH(OCOCH3)COOH ????what will be the product of HOCH2CH(OH)CO2H+CH3CO2H
m/j/09/21/q4 b2
Yes.CH3COOCH2CH(OCOCH3)COOH ????
I assume this is a simple concept. To know whether an atom donates a pair of electrons or shares them to expand it's octet, you have to think about each atom and how many electrons it requires to complete it's octet.
the atom that donates it's pair of electrons has to have at least one pair of lone pair of electrons after it has formed the bond.
also you have to know, that in a dative bond, the electron donor atom donates electrons in pairs. (in the case you mentioned, 3 electrons donated are not in pairs. hence in this case chlorine has to share those 3 electrons with 3 fluorine atoms to expand it's octet.) if an atom has those qualities metioned then in this case it will donate a lone pair instead of expanding it's octet.
you can look at other similar example to help you,
- like Al2Cl6, ( in this case there is no octet expansion taking place)
here each aluminium atom is covalently bonded with 3 chlorine atoms , while at the same time it's accepting a pair of electrons from a forth chlorine atom,,, take a look at the fourth chlorine atom, (as mentioned before the atom donating the pair of electrons has to have at least one pair of electrons after forming the bond, at the same time it donates the electrons in pairs.)
I hope this answers your question
Q8:9701/12/O/N/10
October 2010 paper 1 : Q8 ,Q11 , Q28, Q34, Q39.
Help me please!!
Thanks in advance
A space shuttle’s upward thrust came from the following reaction between aluminium and ammonium perchlorate.
10Al + 6NH4ClO4 → 4Al 2O3 + 2AlCl 3 + 12H2O + 3N2
Which statements about this reaction are correct?
1 Aluminium is oxidised. 2 Chlorine is reduced. 3 Nitrogen is oxidised.
A space shuttle’s upward thrust came from the following reaction between aluminium and ammonium perchlorate.
10Al + 6NH4ClO4 → 4Al 2O3 + 2AlCl 3 + 12H2O + 3N2
Which statements about this reaction are correct?
1 Aluminium is oxidised. 2 Chlorine is reduced. 3 Nitrogen is oxidised.
can explain why answer is C?View attachment 61871
how can u solve itYes.
solve what?how can u solve it
View attachment 61889
can explain why answer is D?
Read This
View attachment 61890
look at (ii) if if there is one alkyl group and one hydrogen at one end of the double bond a carboxylic acid will form ,now look at the question the organic compumd has one alkyl group and one hydrogen on either side of double bond this means two Carboxylic acids will form (COOH) howevver what this pic didnt tell is that if OH is already present in a compund it will always form a COOH.
Using elimination method
A) not possible because double bond has to rupture so 2 molecules have to form so this is not possible. (because its the only link between two group of atoms, THIS MAY NOT HAPPEN IN CYCLIC COMPUNDS)
B)double bond always rupture but this is nt the case since C=C is safe . so this is not possible.
C) although C is partially correct because if we have one alkyl group and one hydrogen at one end of the double bond , first aldehyde is formed , C=C breaks ,1 carbon forms COH. however the process oxidation hasnt ended . the -H in COH also gets an O forming -COOH . thus the end product is -COOH. thus c is not possible
D) Final answer and already told why.
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