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Chemistry: Post your doubts here!

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Wouldn't a lower temperature increase the rate of the forward reaction since it's exothermic? So why is it A instead of D??
 

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The question states that vigorous effervescence occurred, so naturally I would opt for C, because Barium is the most reactive element amongst the other choices.
but isn't it that barium forms the most stable compounds and so they might not decompose on heating under a bunsen burner..through this logic I eliminated C at first :whistle:
 
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http://maxpapers.com/wp-content/uploads/2012/11/9701_w14_qp_11.pdf

40) A reaction pathway diagram is shown.
energy
extent of reaction
Which reactions would have this profile?
1 (CH3)3CBr + NaOH → (CH3)3COH + NaBr
2 CH3CH2Br + NaOH → CH3CH2OH + NaBr
3 (CH3)3CCH2CH2Cl + 2NH3 → (CH3)3CCH2CH2NH2 + NH4Cl

How does one even do this? Answer is D.

1 is a tertiary halogenoalkane, it will undergo SN1 reactions,
  • the reaction will take place in 2 steps
  • the reaction pathway will contain an intermediate state
  • Such reaction paths will be a double hump.

2 and 3 are primary halogenoalkanes, they will undergo SN2 reactions,
  • the reaction will take place in 1 step
  • the reaction pathway will contain an transition state (not an intermediate).
  • Such reaction paths will be a single hump.
 
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