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Chemistry: Post your doubts here!

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how did you guys find p.22?

Has to be the easiest P2 I've seen in a long time. Calculations were easy as was the organic. Infact, organic on this paper was childsplay tbh. Recent papers have had so much tougher organic questions.
 
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AbbbbAr post: 768435 said:
Has to be the easiest P2 I've seen in a long time. Calculations were easy as was the organic. Infact, organic on this paper was childsplay tbh. Recent papers have had so much tougher organic questions.
What was the Ar by the way??
 
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By the way what was the Ar of A? Was it boron? Iykwim
10.8

Hey guys, what if I balanced my equations but i didnt balance it in the simplest form, will i still get the mark?

If you used fractions, yes. If you used decimals, no.

What was the Al2o3 + nacl?

Al2O3 + NaOH -> NaAlO2 + H2O
The first step of this is also acceptable, in that,
Al2O3 + NaOH -> Al(OH)3 + Na

If I write the correct skeletal formula for the wrong ketone will I get a mark?

I don't think. Ecf doesn't come into play here. Usually.
 
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OMG maan, thankyou so freaking much!!! By now I didn't know that we were given the shifts in the booklet!! JazakAllah bro! :)
What r u talking abt ?
''Chemical Shifts''??!!:eek:o_O:unsure::confused:
Exactly my question!!
This is for all the people who have been wondering what the chemical shifts are.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_y14_sy.pdf
This is the link to the 2014 syllabus. Now go onto page 83 which is part of the Data Booklet which we will get during the exam. On this page as you can see clearly the chemical shifts are given which are basically to identify which groups are present in the NMR.
 
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If you used fractions, yes. If you used decimals, no.
Abby, but hmm, all the numbers are times three. Like hmm, you get it?not fractions, but times three like that


Al2O3 + NaOH -> NaAlO2 + H2O
The first step of this is also acceptable, in that,
Al2O3 + NaOH -> Al(OH)3 + Na



I don't think. Ecf doesn't come into play here. Usually.
 
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If you used fractions, yes. If you used decimals, no.



Al2O3 + NaOH -> NaAlO2 + H2O
The first step of this is also acceptable, in that,
Al2O3 + NaOH -> Al(OH)3 + Na



I don't think. Ecf doesn't come into play here. Usually.
Did we have to name A?
 
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If you used fractions, yes. If you used decimals, no.



Al2O3 + NaOH -> NaAlO2 + H2O
The first step of this is also acceptable, in that,
Al2O3 + NaOH -> Al(OH)3 + Na



I don't think. Ecf doesn't come into play here. Usually.
Wut? But my textbook says Al2O3 + NaOH(aq) = NaAl(OH)4
Lemme explain. As the NaOH is aqueous, some water takes part in the reaction too...
 
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