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Hey I've got a question about this chem p5 you guys are talking about above ^
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s11_qp_52.pdf
So for Q2 a) how did you calculate the solubility column?
Like was it just (mass of water) divided by (mass of solid) or something else?
Help would be greatly appreciated
I did as below:
-1 column mass of solid (D-C) in g
-2nd column mass of water (C-B) in g
-3rd column solubility per 100g (E*100) /F
The last parts logic Is as follows:
-Since solubility is to be given in g of solid per 100g of water,
You divide 100 by the mass of water and that given you how much times the solid will be in 100g!