Raiyan3 daredevil
First find the gain in energy to the water using => mc(delta)T
therefore 200*4.2*(66-18) = 40320
As mentioned in the question this is 45% only therefore,
45% => 40320
100% => x
using cross multiplication find x
(100*40320)/45
u will get
89600
The question asked to find per gram...! and tht was for 1.6 gram...therefore
1.6 => 89600
1 => x
cross multiply and u get
(1*89600)/1.6 = 56000
And this is the answer !
First find the gain in energy to the water using => mc(delta)T
therefore 200*4.2*(66-18) = 40320
As mentioned in the question this is 45% only therefore,
45% => 40320
100% => x
using cross multiplication find x
(100*40320)/45
u will get
89600
The question asked to find per gram...! and tht was for 1.6 gram...therefore
1.6 => 89600
1 => x
cross multiply and u get
(1*89600)/1.6 = 56000
And this is the answer !