Chemistry: Post your doubts here!

[Eugene99]

I can understand until B is added to dilue H2S04 and we get 2hydroxycarboxylic acid but how does adding conc H2SO4, with heat, gets us CH2=CHCO2H and what reaction is this?

 

[qwertypoiu]

View attachment 59849
I can understand until B is added to dilue H2S04 and we get 2hydroxycarboxylic acid but how does adding conc H2SO4, with heat, gets us CH2=CHCO2H and what reaction is this?

This is dehydration of alcohol. It removes an H2O molecule from the alcohol by removing the OH group and an H from the adjacent carbon atom. An alkene is formed. This type of reaction is also known as elimination.
There are other reagents and conditions that can be used like heated alumina (Al2O3) or hot porous pumice (or something like that )

 

[Eugene99]

 

[Eugene99]

This is dehydration of alcohol. It removes an H2O molecule from the alcohol by removing the OH group and an H from the adjacent carbon atom. An alkene is formed. This type of reaction is also known as elimination.
There are other reagents and conditions that can be used like heated alumina (Al2O3) or hot porous pumice (or something like that )

oh thanks a lot! I get that but I was confused because it was a carboxylic acid, wasn't it?

 

[qwertypoiu]

oh thanks a lot! I get that but I was confused because it was a carboxylic acid, wasn't it?

Well yes it did have a carboxylic acid group but I do not know of any reaction that the carboxylic acid group undergoes with H2SO4. However, there WAS the alcohol group so we ignore the acid group and concentrate on the alcohol.

 

[qwertypoiu]

View attachment 59850

The ester group is broken.
OH from water joins the C=O part to form COOH.
H from water joins the O part to form OH.
So when HCO2CH(CH3)R is hydrolysed,
HCO2H and RCH(CH3)OH is formed

 

[ashcull14]

sorry i knw tht im asking the dumbest quebut seriously ive not been through this chapter properly ..can anyone help?? part 2

 

[Eugene99]

Well yes it did have a carboxylic acid group but I do not know of any reaction that the carboxylic acid group undergoes with H2SO4. However, there WAS the alcohol group so we ignore the acid group and concentrate on the alcohol.

Yes exactly!

 

[The Sarcastic Retard]

sorry i knw tht im asking the dumbest quebut seriously ive not been through this chapter properly ..can anyone help?? part 2View attachment 59854

You now know the rate equation.
Rate = [NO][O2] (both have powers of its order) for example NO is 2nd order and O2 is 1st order the rate equation will be [NO]^2.[O2]

You have value of concentrations. Substitute and your life is now easy xD
good luck.

 

[Eugene99]

Sodium hydrogencarbonate is the same as sodium bi-carbonate?

 

[My Name]

Sodium hydrogencarbonate is the same as sodium bi-carbonate?

Yep.

 

[ashcull14]

You now know the rate equation.
Rate = [NO][O2] (both have powers of its order) for example NO is 2nd order and O2 is 1st order the rate equation will be [NO]^2.[O2]

You have value of concentrations. Substitute and your life is now easy xD
good luck.

well i knw tht but i didnt get hw is this the ans in MS
(0.00408 × 27) rate = 0.11 (mol dm–3 s–1) to 2sf

 

[The Sarcastic Retard]

well i knw tht but i didnt get hw is this the ans in MS
(0.00408 × 27) rate = 0.11 (mol dm–3 s–1) to 2sf

Look at this.
I compared 1st and 4th experiment.

In ms its opposite of what i did.
denominator part is numerator and vice versa.

 

[The Sarcastic Retard]

well i knw tht but i didnt get hw is this the ans in MS
(0.00408 × 27) rate = 0.11 (mol dm–3 s–1) to 2sf

In ms its same thing. That 27 came from the comparision of 4th and 1st experiment ratio.

 

[Sariya Khan]

Can't the hydroxyl group react directly with cyanide ion?

 

[The Sarcastic Retard]

Can't the hydroxyl group react directly with cyanide ion?

I havent seen any reaction like this till now.

 

[Sariya Khan]

I havent seen any reaction like this till now.

Hahah so it doesn't. Thanks ^_^

 

[Eugene99]

How does, acidifying the pool water, not let the OCl to break down?

 

[Eugene99]

Please explain

 

[Eugene99]

Why is it A?